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Ranking in Access

I have an access table that has points calulated.

vendor 1
Rating 1  60 pts
Rating 2  40 pts
Rating 3  40 pts
Rating 4  30 pts
Rating 5  20 pts

I have created a query that ranks the ratings.  It comes out so:
1
2
2
4
5

What I need it to do is a distinct rating like so:
1
2
2
3
4
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Entrapenuer
CERTIFIED EXPERT
Commented:
that makes no sense. can you please provide a screenshot

Commented:
Do a
Select Distinct Ranking
dbasetroublePurchasing

Author

Commented:
Snapshot of Table.Here is a screen snap shot of the Database table.  I need ranking according to the points column.  There is a tie.  I need the rank to look like this:
1
2
2
3
4
Not
1
2
2
4
5

Commented:
I see your problem, I don't have an answer for that off the top of my head. Sorry!
Ess KayEntrapenuer
CERTIFIED EXPERT

Commented:
1        one solution is to order it by rating, then take the row number


2          another is to use WITH TIES

source: http://harriyott.com/2007/06/with-ties-sql-server-tip.aspx

SELECT TOP 5 WITH TIES Name, Score
FROM Scores
ORDER BY Score DESC

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Which gives:

Name      Score
Brenda      42
Maureen      41
Edwin      41
Terry      40
Rupert      39
Arthur      39
Paula      39




If you choose to use the second method. You can query into it from another query and select the rankings that way
Ess KayEntrapenuer
CERTIFIED EXPERT

Commented:
Actually this will probably work better



SELECT * FROM
 (SELECT id, points from member1 )Y INNER JOIN
(SELECT DISTINCT points, count(*)as rating FROM member1 GROUP BY points ORDER BY points )X ON Y.points = X.points
ORDER BY Points
dbasetroublePurchasing

Author

Commented:
Thanks for the help.  Figured out a much easier way.  I created a query call distinctrank.  I added just the points field and change the query properties to uniquevalue=Yes.  I then create a expression field in the regular query that looks like this:

Rank1: DCount("*","distinctrank","Points >" & [Points])+1

Work out great.
Ess KayEntrapenuer
CERTIFIED EXPERT

Commented:
great to hear, if you have a large table the last one i added might work quicker, but it looks like you might not need it

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