• Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 280
  • Last Modified:

not able to get rid of trailing space in my column

I want to join two tables on ImageFilename  column. the name is the same in both the tables, except for a trailing space in Table B. S, I am using Replace function to get rid of the space, but still can't get rid of the space. What 's wrong with my join?

Select A.ImageFileName, B.ImageFileName
From [MyDB].[dbo].[TableA] A
join  [MyDB].[dbo].[TableB] B on Replace(A.ImageFileName, ' ', '') = Replace(B.ImageFileName, ' ', '')

Sample data: (I added a * at both the ends to give you an idea of what's happening.
Table A:

Table B:
*H3708_079019200_731481229001_UNIH3708HD12.pdf *
*H3708_079020195_731420444101_UNIH3708HD12.pdf *
*H3708_079020206_731481229001_UNIH3708HD12.pdf *
*H3708_079020210_731461537101_UNIH3708HD12.pdf *

if I manually edit Table B to remove trailing space, it joins.

How should I proceed without the mannual edit?

1 Solution
Patrick TallaricoFSEP Systems AnalystCommented:
I may make sense to have the spaces removed as the table is populated.  This way there is less work to be done for the join when the query is run.
I am assuming there is a process to read filenames from a server and input this into the table on the sql server.

Just curious, if you re-arrange your query to pull from subqueries where the Replace function is performed before the join, does it work?
It should look something like this...

Select A.AFileName, B.BFileName
From (Select Replace(ImageFileName, ' ', '') as [AFileName] from [MyDB].[dbo].[TableA]) as A
join  (Select Replace(ImageFileName, ' ', '') as [BFileName] from [MyDB].[dbo].[TableB]) as B on A.AFileName = B.BFileName
Martin LissOlder than dirtCommented:
It's probably not a space. Could it be a carriage return? You can use something like

MsgBox Asc(Right(A.ImageFileName, 1))

to find out what it is and then use Replace with Asc(nn) instead of the " ", where 'nn' is the ascii value.
patd1Author Commented:
It was a tab, not a space.
This finally works by joining on
 Replace(A.ImageFileName, CHAR(9), '') = Replace(B.ImageFileName, CHAR(9), '')
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Featured Post

Free Tool: Subnet Calculator

The subnet calculator helps you design networks by taking an IP address and network mask and returning information such as network, broadcast address, and host range.

One of a set of tools we're offering as a way of saying thank you for being a part of the community.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now