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How to get an IPAddress from within a CodeBehind aspx page

I am trying to get the users IPAddress....from within a CodeBehind aspx page.

This is on my aspx page... test.aspx
which refers to --> CodeBehind="test.aspx.vb"

My function is this.....(inside test.aspx.vb)
    Public Shared Function getIPAddress()
        Dim IPAddress As String = ""
        IPAddress = Request.ServerVariables("REMOTE_ADDR")
        Return IPAddress
    End Function

The error I get is this.....
Cannot refer to an instance member of a class from within a shared method or shared member initializer without an explicit instance of the class.

Can I get the IPAddress directly from inside the CodeBehind page?
Can I get it from the aspx page & pass it to the CodeBehind page?
0
MikeCombe
Asked:
MikeCombe
  • 3
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2 Solutions
 
veeraCommented:
Hi,

try this

Dim strClientIp As String = Request.UserHostAddress()

OR

Dim strClientIP As String = HttpWorkerRequest.GetRemoteAddress().ToString()

OR

Dim strClientIP As String = Context.Request.ServerVariables("REMOTE_ADDR")
0
 
MikeCombeAuthor Commented:
same error....using

    Public Shared Function getIPAddress()
        Dim IPAddress As String = ""
        IPAddress = Request.UserHostAddress()
        IPAddress = HttpWorkerRequest.GetRemoteAddress().ToString()
        IPAddress = Context.Request.ServerVariables("REMOTE_ADDR")
        Return IPAddress
    End Function
0
 
Rose BabuSenior Team ManagerCommented:
This will work correctly.
Dim IPAddress As String = ""
IPAddress = Request.UserHostName

Open in new window

Try this.
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MikeCombeAuthor Commented:
nope.....same error. see attached graphic.
IPAddress.png
0
 
Rose BabuSenior Team ManagerCommented:
May i know, Why did you declare the getIPAddress() function as a shared function?
Public Function getIPAddress()
        Dim IPAddress As String = ""
        IPAddress = Request.UserHostName
        Return IPAddress
End Function

Open in new window

Can u make the function as non-shared function and test once?
0
 
Rose BabuSenior Team ManagerCommented:
any luck?
0

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