Trouble with getting text file into 2D array

I have been searching the posts but can't find enough help within them to get me over the hump here.  I have a text file that that I am trying to read into a 2D array.  The first line has the number of records in the file and the remaining lines look like this:
111111  NAME  NAME  TITLE  00.0  0.00
Each separation is a new column in the array but they can be entered as String, there is no need for the numbers to come in as integers or doubles (with the exception of the very first line that contains the number of records in the file).  I have been working on this for days and cannot seem to figure this out.  When I run this code I don't get any errors but what happens with this test at the end is "This is a test null" and what I expect to see is "This is a test Senior."  Obviously my array is empty but I am not sure why.  This is my code:

import java.io.*;
import java.util.*;

public class TestProgram
{
   public static void main(String args[])
     {
        try
        {
	BufferedReader in = new BufferedReader(new FileReader("students.txt"));
		int x=0, y=0, row = 0;
		row = Integer.parseInt(in.readLine());
		String line;
		String[][] students = new String[row][6];
		while ((line = in.readLine()) != null)	
		{
		   String[] values = line.split("  ");

                           for (String str : values)
	        	   {
	        	     students[x][y]=str;
	         	   }
		}

            in.close();
            System.out.println("This is a test " + students[3][3]);

            }catch( IOException ioException ) {}
     }

}

Open in new window

jwhmackAsked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

for_yanCommented:
You are printing "This is a test " + students[3][3]

but your students arary is out of scope at this palce you sghould declare studesnts array aas an onstance variable not within the redaing loop
0
for_yanCommented:
try this way:

import java.io.*;
import java.util.*;

public class TestProgram
{
   public static void main(String args[])
     {
String[][] students; 

        try
        {
	BufferedReader in = new BufferedReader(new FileReader("students.txt"));
		int x=0, y=0, row = 0;
		row = Integer.parseInt(in.readLine());
		String line;
		students = new String[row][6];
		while ((line = in.readLine()) != null)	
		{
		   String[] values = line.split("  ");

                           for (String str : values)
	        	   {
	        	     students[x][y]=str;
	         	   }
		}

            in.close();
            System.out.println("This is a test " + students[3][3]);

            }catch( IOException ioException ) {}
     }

}
                                  

Open in new window

0
for_yanCommented:
Post your students.txt file and I'll try to debug it
0
Rowby Goren Makes an Impact on Screen and Online

Learn about longtime user Rowby Goren and his great contributions to the site. We explore his method for posing questions that are likely to yield a solution, and take a look at how his career transformed from a Hollywood writer to a website entrepreneur.

for_yanCommented:
You also never increment x or y
0
for_yanCommented:
try this code:

import java.io.*;
import java.util.*;

public class TestProgram
{
   public static void main(String args[])
     {
String[][] students;

        try
        {
	BufferedReader in = new BufferedReader(new FileReader("students.txt"));
		int x=0, y=0, row = 0;
		row = Integer.parseInt(in.readLine());
		String line;
		students = new String[row][6];
		while ((line = in.readLine()) != null)
		{
		   String[] values = line.split("[\\s]+");

                           y=0;

                           for (String str : values)
	        	   {
                       //System.out.println("str: " + str);
	        	     students[x][y]=str;
                       y++;
	         	   }

            x++;
		}

            in.close();
            System.out.println("This is a test " + students[3][3]);

            }catch( IOException ioException ) {}
     }

}

Open in new window

0
for_yanCommented:
The above code with this input file students.txt

5
111111  NAME  NAME  TITLE  00.0  0.00
111111  NAME  NAME  TITLE  00.0  0.00
111111  NAME  NAME  TITLE  00.0  0.00
111111  NAME  NAME  TITLE  00.0  0.00
111111  NAME  NAME  TITLE  00.0  0.00

Open in new window


gives this result:

This is a test TITLE

Open in new window

0
for_yanCommented:
So your code had number of issues:

1) you tried to use array students out opf scope of its ddeclatain
I declaread it immediately in the main() so that its scope becomes the whole method

2) you were assigning    students[x][y]=str;
all the time to students[0][0] because x and y were not being incremneneted after assignemnt

3) method split(..) uses regexpression
if you split by any number of spaces or tabs you need to provide adequate regex
(see the one I put in the code)

I think those were the main issues; try to run this code with your real file
and see if youi get the output you want
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
jwhmackAuthor Commented:
Bingo, that was it.  I thought my code seemed a bit simple.  Thank you.  I had originally had th array in the main but I couldn't get the row variable to work like I said but it didn't occur to me to just initialize in the main and then call it again inside the try.  I am still learning on a lot of this stuff as you can tell.  Java is definitely a weak spot for me.  So is the \\s for spaces and if I had only had a single space between the values would I have used \s instead of \\s?
0
CEHJCommented:
Each separation is a new column in the array but they can be entered as String, there is no need for the numbers to come in as integers or doubles (with the exception of the very first line that contains the number of records in the file).

There's not much point in representing them as type String since they are clearly not strings in some cases. You should really have them as an array of beans, or failing that (and something you should really avoid) as Object[][]
0
for_yanCommented:
>So is the \\s for spaces and if I had only had a single space between the values would I have used \s instead of \\s?

No, that is not true "\s" will just cause compiler error in this case

Regular Expressions is a big topic - you can start reading about them
here:
http://www.regular-expressions.info/

or about some detials of Java implementation here:

http://docs.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html

On the other hand be prepared to spend some significant time on this subject, so if you are now studying java just take for granted some simple expresssion like the one in your code above, and when you have some time later spend it on studying RegEx specifically.
This expression will allow you to split the line into items seprated by one as well as by more than one spaces.
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Java

From novice to tech pro — start learning today.