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Posted on 2012-03-14
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Last Modified: 2012-03-15
For a real estate site.....

I have a table named 'properties' which hold all of the properties details and another called 'featured' which states which properties are features.

The 'featured' table has the columns id (primary) and property_id which relates to the id on the properties table.

I basically need to know the query to display the featured properties which, at the moment would be properties with the id's 15,16 & 17 (see attachment)
Screen-shot-2012-03-14-at-10.01..png
Screen-shot-2012-03-14-at-10.01..png
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Question by:BrighteyesDesign
6 Comments
 
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Assisted Solution

by:theGhost_k8
theGhost_k8 earned 250 total points
ID: 37719669
select p.* from properties p, featured f where p.propertyid=f.property_id and f.property_id in (15,16,17);

Check if this works for you! You will have to write condition after first where condition based on what you're choosing featured properties to be displyed?
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Author Comment

by:BrighteyesDesign
ID: 37719967
Hi, thanks for that

Just one thing...15,16 & 17 are just the id's of what should show. They shouldn't be part of the query.

The query needs to be...Display properties from the 'properties' table if their ID is in the property_id column of the 'featured' table

Hope this makes sense!
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LVL 8

Expert Comment

by:Santhana
ID: 37720111
SELECT  p.*  FROM properties p ,featured f
WHERE p.property_id= f.property_id;
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Expert Comment

by:Derokorian
ID: 37720127
SELECT p.* FROM featured
   LEFT JOIN  properties as p
      ON propertyID = property_id

Open in new window

Should give you what you are looking for. HTH
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Accepted Solution

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Ray Paseur earned 250 total points
ID: 37720366
I think I might let the "featured" fact be a column in the properties table.  It's not relational to anything else as far as I can see.  Then it would be SELECT things FROM table WHERE featured = 1 (or something to that effect).
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LVL 21

Expert Comment

by:theGhost_k8
ID: 37723878
That's what I meant by this I wrote earlier >>>"You will have to write condition after first where condition based on what you're choosing featured properties to be displyed?"

Btw, joins will help you out but a boolean column will ease out your task!
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