shell script question

I have a script was not sure what does it do:

"$JAVA_HOME/bin/java" \
"$OSGI_INSTALL" "$OSGI_CFG" \
$EXTRA_X_ARG \
$CONSOLE_ENCODING \
-Dcom.ibm.websphere.migration.serverRoot="$WAS_HOME" \
-Dws.ext.dirs="$WAS_EXT_DIRS" \
-Dwas.install.root=$WAS_HOME \
-Duser.install.root=$USER_INSTALL_ROOT \
$PERF_JVM_OPTIONS \
$WAS_LOGGING \
$EXTRA_D_ARG \
-classpath "$WAS_CLASSPATH":"$WAS_HOME"/derby/lib/derby.jar com.ibm.wsspi.bootstrap.WSPreLauncher \
-nosplash -application com.ibm.ws.bootstrap.WSLauncher com.ibm.ws.migration.WASPreUpgrade "$@"

the reason I am asking is that I want to run the command WASPreUpgrade with an argument. where do I add that argument?

thanks,

Linux

Last Comment

DESEI-SELB

8/22/2022 - Mon

simon3270

3/14/2012

The script already passes any arguments to the WASPreUpgrade program as "$@" at the end of the last line.

Just add the argument(s) to the command line.

DESEI-SELB

3/14/2012

ASKER

is "$@" only goes for WASPreUpgrade or for the other two application too(WSLauncher, WSPreLauncher)? thanks.

DESEI-SELB

3/14/2012

ASKER

also, the WASPreUpgrade is not being run from the command line but from a different script. so can I just add the argument at the end aftger "$@"?

thanks,

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William Peck

ASKER CERTIFIED SOLUTION

simon3270

3/14/2012

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