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jQuery - Pagination of Visible Results?

Hello,

I'm trying to paginate only visible results, after they have been filtered (made hidden or visible) by other jQuery controls. The plugins I have tried seem to ignore the filtering controls, by not updating the pagination after a filter has been applied or removed. How would I go about this? Printing a count of visible/total for the user would be a nice touch.

An unpaginated sample is available here. Many thanks to mplungjan, as this is the result of our Filter Results by More Than 2 Intersections discussion.

Any help is much appreciated.
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Michel Plungjan
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Here is what I have so far. Not working at all but I really need to get away from the computer after 13 hours behind one

<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<script src="https://raw.github.com/infusion/jQuery-Paging/master/jquery.paging.min.js"></script>
<script>
function onSelectCB() {}
function onFormatCB() {}


$(document).ready(function() {
    $('input:checkbox').attr('checked', 'checked');
    $(".chk").click(function() {
        $(".chk:checked").each(function() {
           $("."+this.id).show();
        });       
        $(".chk:not(:checked)").each(function() {
           $("."+this.id).hide();
           $("#content").empty();
           if ($(".courseBox:visible").length > 0) {
             $(".courseBox:visible").each(function() {
               var elem =$('<div>').attr("class","element").html($(this).html()); 
               $("#content").append(elem);      
             });
             $(".pagination").paging(1000, { // make 1000 elements navigatable
               format: '[< ncnnn! >]', // define how the navigation should look like
               perpage: 4, // show 4 elements per page
               lapping: 0, // don't overlap pages for the moment
               page: 1, // start at page, can also be "null" or negative
               onSelect: onSelectCB, // callback is called when user selects a page
               onFormat: onFormatCB // callback is called once for every "format" element
             });    
           }
        });        
    });        
});    
</script>
<style>
input {margin:0 0 10px 0;}
li {margin:5px 0px;}
</style>
<body>
<label><input class="chk" type="checkbox" checked="checked" id="course">Courses</label>
<label><input class="chk" type="checkbox" checked="checked" id="morning">Morning</label>
<label><input class="chk" type="checkbox" checked="checked" id="evening">Evening</label>
<div class="pagination toppagination"></div>
<div id="content">

</div>
<div class="pagination toppagination"></div>
	

<ul>
<li class="courseBox course">Course One</li>
<li class="courseBox course evening">Course One, Evening</li>
<li class="courseBox morning">Morning One</li>
<li class="courseBox course">Course Two</li>
<li class="courseBox course evening">Course Two, Evening</li>
<li class="courseBox morning">Morning Two</li>
<li class="courseBox course">Course Three</li>
<li class="courseBox course evening">Course Three, Evening</li>
<li class="courseBox morning">Morning Three</li>
<li class="courseBox course">Course Four</li>
<li class="courseBox course evening">Course Four, Evening</li>
<li class="courseBox morning">Morning Four</li>
<li class="courseBox course">Course Five</li>
<li class="courseBox course evening">Course Five, Evening</li>
<li class="courseBox morning">Morning Five</li>
<li class="courseBox course">Course Six</li>
<li class="courseBox course evening">Course Six, Evening</li>
<li class="courseBox morning">Morning Six</li>
</ul>

<span id="msg"></span>
</body>
</html>

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que-es

ASKER

I've taken several passes at altering the above code to achieve paginated display of visible elements, but so far no dice. Any further insight/input would be appreciated.
Yeah, sorry I did not get it done. I'll push the "Request Attention" for you
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ASKER

It's OK, & thank you.
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ASKER

Hi,

The request for help was sent on 3/31, though nothing further has happened. Does anyone have a suggestion to resolve this question?

Thanks.
I'll take one more look tomorrow
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ASKER

Thanks very much!
ASKER CERTIFIED SOLUTION
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Michel Plungjan
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ASKER

That is fantastic, thank you. I have been going through it to understand your process & how it works. Will integrate it into the larger solution tomorrow and report back. Sending you that email.
I've requested that this question be deleted for the following reason:

The question has either no comments or not enough useful information to be called an "answer".
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ASKER

The conversation started by the poster's solution was very informative, and I learned from it.
Thanks - Me too. This is one reason I answer questions here for free :)
Here is the code from the jsFiddle

/* Filtering and pagination
   (c) 2012 Michel Plungjan - javascripts(a)plungjan.name */
var max = 5,cnt=0,sel,selLength; 
$(document).ready(function() {
    $('input:checkbox').attr('checked', 'checked');
    $(".chk").click(function() {
        $(".chk:checked").each(function() {
           $("."+this.id).show();
        });       
        $(".chk:not(:checked)").each(function() {
           $("."+this.id).hide();
        });
        init();
    });
    init();
}); 
function init() {
  cnt=0;
  sel = $("li:visible");
  selLength = sel.length;
  go(0);      
}
function nav() {
  var nav = $("#nav").empty();   
  if(selLength==0) {
    nav.append("Selection did not result in any courses");
    return;
  }        
  nav.append((cnt==0)?'<span class="disabled"><</span>':'<a href="#" onclick="return go(-1)"><b><</b></a>');
  var end = cnt+max;

  if (end > selLength) end = selLength;

  nav.append("&nbsp;"+(cnt+1)+"-"+end+" of "+selLength+"&nbsp;");
  nav.append((end>=selLength)?'<span class="disabled">></span>':'<a href="#" onclick="return go(1)"><b>></b></a>');
}
function go(dir) {
  if (dir<0) cnt-=max;  
  if (dir==1) cnt+=max;
  sel.hide();
  for (var i=cnt,n=0;i<selLength && n<max;i++,n++) {
    sel.eq(i).show();  
  }
  nav();
}    

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