jQuery - Pagination of Visible Results?


I'm trying to paginate only visible results, after they have been filtered (made hidden or visible) by other jQuery controls. The plugins I have tried seem to ignore the filtering controls, by not updating the pagination after a filter has been applied or removed. How would I go about this? Printing a count of visible/total for the user would be a nice touch.

An unpaginated sample is available here. Many thanks to mplungjan, as this is the result of our Filter Results by More Than 2 Intersections discussion.

Any help is much appreciated.
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Michel PlungjanIT ExpertCommented:
Here is what I have so far. Not working at all but I really need to get away from the computer after 13 hours behind one

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<script src="https://raw.github.com/infusion/jQuery-Paging/master/jquery.paging.min.js"></script>
function onSelectCB() {}
function onFormatCB() {}

$(document).ready(function() {
    $('input:checkbox').attr('checked', 'checked');
    $(".chk").click(function() {
        $(".chk:checked").each(function() {
        $(".chk:not(:checked)").each(function() {
           if ($(".courseBox:visible").length > 0) {
             $(".courseBox:visible").each(function() {
               var elem =$('<div>').attr("class","element").html($(this).html()); 
             $(".pagination").paging(1000, { // make 1000 elements navigatable
               format: '[< ncnnn! >]', // define how the navigation should look like
               perpage: 4, // show 4 elements per page
               lapping: 0, // don't overlap pages for the moment
               page: 1, // start at page, can also be "null" or negative
               onSelect: onSelectCB, // callback is called when user selects a page
               onFormat: onFormatCB // callback is called once for every "format" element
input {margin:0 0 10px 0;}
li {margin:5px 0px;}
<label><input class="chk" type="checkbox" checked="checked" id="course">Courses</label>
<label><input class="chk" type="checkbox" checked="checked" id="morning">Morning</label>
<label><input class="chk" type="checkbox" checked="checked" id="evening">Evening</label>
<div class="pagination toppagination"></div>
<div id="content">

<div class="pagination toppagination"></div>

<li class="courseBox course">Course One</li>
<li class="courseBox course evening">Course One, Evening</li>
<li class="courseBox morning">Morning One</li>
<li class="courseBox course">Course Two</li>
<li class="courseBox course evening">Course Two, Evening</li>
<li class="courseBox morning">Morning Two</li>
<li class="courseBox course">Course Three</li>
<li class="courseBox course evening">Course Three, Evening</li>
<li class="courseBox morning">Morning Three</li>
<li class="courseBox course">Course Four</li>
<li class="courseBox course evening">Course Four, Evening</li>
<li class="courseBox morning">Morning Four</li>
<li class="courseBox course">Course Five</li>
<li class="courseBox course evening">Course Five, Evening</li>
<li class="courseBox morning">Morning Five</li>
<li class="courseBox course">Course Six</li>
<li class="courseBox course evening">Course Six, Evening</li>
<li class="courseBox morning">Morning Six</li>

<span id="msg"></span>

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que-esAuthor Commented:
I've taken several passes at altering the above code to achieve paginated display of visible elements, but so far no dice. Any further insight/input would be appreciated.
Michel PlungjanIT ExpertCommented:
Yeah, sorry I did not get it done. I'll push the "Request Attention" for you
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que-esAuthor Commented:
It's OK, & thank you.
que-esAuthor Commented:

The request for help was sent on 3/31, though nothing further has happened. Does anyone have a suggestion to resolve this question?

Michel PlungjanIT ExpertCommented:
I'll take one more look tomorrow
que-esAuthor Commented:
Thanks very much!
Michel PlungjanIT ExpertCommented:
Here is my work in progress


I would like you to email me - my email is in my profile

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que-esAuthor Commented:
That is fantastic, thank you. I have been going through it to understand your process & how it works. Will integrate it into the larger solution tomorrow and report back. Sending you that email.
RobOwner (Aidellio)Commented:
I've requested that this question be deleted for the following reason:

The question has either no comments or not enough useful information to be called an "answer".
que-esAuthor Commented:
The conversation started by the poster's solution was very informative, and I learned from it.
Michel PlungjanIT ExpertCommented:
Thanks - Me too. This is one reason I answer questions here for free :)
Here is the code from the jsFiddle

/* Filtering and pagination
   (c) 2012 Michel Plungjan - javascripts(a)plungjan.name */
var max = 5,cnt=0,sel,selLength; 
$(document).ready(function() {
    $('input:checkbox').attr('checked', 'checked');
    $(".chk").click(function() {
        $(".chk:checked").each(function() {
        $(".chk:not(:checked)").each(function() {
function init() {
  sel = $("li:visible");
  selLength = sel.length;
function nav() {
  var nav = $("#nav").empty();   
  if(selLength==0) {
    nav.append("Selection did not result in any courses");
  nav.append((cnt==0)?'<span class="disabled"><</span>':'<a href="#" onclick="return go(-1)"><b><</b></a>');
  var end = cnt+max;

  if (end > selLength) end = selLength;

  nav.append("&nbsp;"+(cnt+1)+"-"+end+" of "+selLength+"&nbsp;");
  nav.append((end>=selLength)?'<span class="disabled">></span>':'<a href="#" onclick="return go(1)"><b>></b></a>');
function go(dir) {
  if (dir<0) cnt-=max;  
  if (dir==1) cnt+=max;
  for (var i=cnt,n=0;i<selLength && n<max;i++,n++) {

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