Find the first space in a string and only return the characters before that space using vba
Is there an easy way to find in a string and only return the characters before the first space in the string.
For example: married divorce single blabla
should return married in this example
many thanks!!
For example: married divorce single blabla
should return married in this example
many thanks!!
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The following will break up the source string [the first argument to Split()] using the second argument as the delimiter.
The delimter may be more than one character in length.
If the source string is empy then the size of the array will be -1.
If the delimter is not found then the whole string is returned in element 0 of the array.
'-------------------------
Dim mystring() As String
Sub testme()
mystring = Split("this is a sample string", " ")
if ubound(mystring) >= 0 then
Debug.Print mystring(0)
endif
End Sub
The delimter may be more than one character in length.
If the source string is empy then the size of the array will be -1.
If the delimter is not found then the whole string is returned in element 0 of the array.
'-------------------------
Dim mystring() As String
Sub testme()
mystring = Split("this is a sample string", " ")
if ubound(mystring) >= 0 then
Debug.Print mystring(0)
endif
End Sub
Left(yourfield , instr(yourfield & " ", " ")-1)