Solved

MS SQL Server -- substring DateTime ?

Posted on 2012-03-15
5
854 Views
Last Modified: 2012-03-16
Below works, updating the value
to 2012-03-15 09:17:24.910

How can I change so it always
keeps the end as "02:00:00.000" ?

update [ReportServer].[dbo].[Schedule]
--set [StartDate] = '2012-03-30' + substring([StartDate],11,13)
set [StartDate] = CURRENT_TIMESTAMP,
    [NextRunTime] = CURRENT_TIMESTAMP
where [Name] like 'EOM - 3:30a%'
0
Comment
Question by:finance_teacher
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
5 Comments
 
LVL 7

Assisted Solution

by:micropc1
micropc1 earned 100 total points
ID: 37725398
Try...

UPDATE [ReportServer].[dbo].[Schedule]
SET StartDate = CAST(CAST(YEAR(GETDATE()) AS varchar) + '-' + CAST(MONTH(GETDATE()) AS varchar) + '-' + CAST(DAY(GETDATE()) AS varchar) + ' 02:00' AS DATETIME)
WHERE [Name] LIKE 'EOM - 3:30a%'

Open in new window

0
 
LVL 69

Expert Comment

by:Scott Pletcher
ID: 37725432
UPDATE [ReportServer].[dbo].[Schedule]
SET
    [StartDate] = CONVERT(char(8), CURRENT_TIMESTAMP, 112) + ' 02:00:00.000',
    [NextRunTime] = CONVERT(char(8), CURRENT_TIMESTAMP, 112) + ' 02:00:00.000'
WHERE
    [Name] LIKE 'EOM - 3:30a%'
0
 

Author Comment

by:finance_teacher
ID: 37726131
Below works, but how can I get the "substring"
to work since I have 50+ updates and want to
use a substring of the original StartDate value without
getting an Argument data type datetime is invalid for
argument 1 of substring function ERROR ?
------------------------------------------------------------------------------
UPDATE [ReportServer].[dbo].[Schedule]
SET StartDate =
         CAST(
                 CAST('2012-03-19' AS varchar) +
                 ' 03:30' AS DATETIME
                          --substring([StartDate],11,13) AS DATETIME
             )
WHERE [Name] LIKE 'EOM - 3:30a%'
0
 
LVL 69

Expert Comment

by:Scott Pletcher
ID: 37726569
Oh, OK, you don't always want 02:00:00.000, you want to retain the original time --
right?.

Btw, the format YYYYMMDD is *universal* in SQL Server and *always* works, but YYYY-MM-DD is not can fail under certain settings.


UPDATE [ReportServer].[dbo].[Schedule]
SET StartDate =
         CAST(
                 '20120319 ' + CONVERT(varchar(20), startDate, 114)
             )
WHERE [Name] LIKE 'EOM - 3:30a%'


SQL will automatically convert the varchar value to datetime if/when needed.
0
 
LVL 69

Accepted Solution

by:
Scott Pletcher earned 400 total points
ID: 37726576
If you just need to adjust the number of days, and keep exactly the same time, this would be faster:

SET StartDate = DATEADD(DAY, DATEDIFF(DAY, StartDate, '20120319'), StartDate)
0

Featured Post

U.S. Department of Agriculture and Acronis Access

With the new era of mobile computing, smartphones and tablets, wireless communications and cloud services, the USDA sought to take advantage of a mobilized workforce and the blurring lines between personal and corporate computing resources.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Load balancing is the method of dividing the total amount of work performed by one computer between two or more computers. Its aim is to get more work done in the same amount of time, ensuring that all the users get served faster.
Ever needed a SQL 2008 Database replicated/mirrored/log shipped on another server but you can't take the downtime inflicted by initial snapshot or disconnect while T-logs are restored or mirror applied? You can use SQL Server Initialize from Backup…
Familiarize people with the process of retrieving data from SQL Server using an Access pass-thru query. Microsoft Access is a very powerful client/server development tool. One of the ways that you can retrieve data from a SQL Server is by using a pa…
This video shows how to set up a shell script to accept a positional parameter when called, pass that to a SQL script, accept the output from the statement back and then manipulate it in the Shell.

733 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question