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Batch file to delete sequential lines of text in a text file

Thanks for any help that you can give me. I need a batch file that can delete lines from a text file, each line begins with a time, and I need to delete everything between 5:00am and 11:00am, so that I can automate daily editing of the file. Please be gentle with me, as I am new to batch files;)

Text File is attached for example of what I need to edit

As you can see, the lines begin with a time, so I don't think it would be too hard, but I need it to take everything between 5am and 11am out and then save the text file without those hours.

Thanks again!
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1 Solution
Try this; you can pass the file to filter either directly in the command line, drag and drop a file in Explorer on the script, or you'll be queried.
The script will generate a file with the same name as the input file, but "-filtered" attached.
You've noticed that there are "times" like "00:77:07"?
@echo off
setlocal enabledelayedexpansion
if "%~1"=="" (
  echo Please pass the name of the file to filter as command line argument,
  echo or "drag and drop" the file onto the script or this window, or enter the file name:
  set /p InFile=^>
) else (
  set InFile=%~1
if not exist "%InFile%" (
  echo File not found: %InFile%
  goto :eof
set OutFile=%~dpn0-filtered.txt
if exist "%OutFile%" del "%OutFile%"
for /f "delims=" %%a in ('type "%InFile%"') do (
  set Print=0
  set Time=%%a
  set /a Hour=1!Time:~1,2!
  if "!Hour!" LSS "105" set Print=1
  if "!Hour!" GTR "111" set Print=1
  if !Print!==1 (
    echo %%a
    >>"%OutFile%" echo %%a
echo Done.

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rodthetripodAuthor Commented:
You are a batch file GOD! Works absolutely perfectly! THANK YOU!
I am aware of the hours that are more than 60 minutes ex: "4:75", but those are handled by the automation software, so no worries there.

Once again thanks, I really appreciate it.

Steve KnightIT ConsultancyCommented:
You have your answer I can see, but a possibly simpler way programming wise is just to use the FINDSTR command .... I had typed this earlier but called away:

This takes the file 120308.txt and excludes all lines that start with

. = any char to match the "
0 = to match the 0
[5-9] = to match 5,6,7,8,9
: to match the colon.

and then runs an exclusion for lines that start "10:" and sends the output into a file called output.txt

findstr /V /B /R /C:".0[5-9]:" 120308.txt | findstr /V /B /R /C:".10:" > output.txt

I was trying to think of a better way to exclude the 10 using the same FINDSTR but failed!

rodthetripodAuthor Commented:
Thanks Steve, I will try that out too....nothing wrong with simplifying things....right?
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