<div>
I don't knw which of the parameters the compiler complains about (since all input parameters to 'strstr()' usually are 'const char*'), but maybe a 'const_cast&lt;char*&gt;()' can help, see <a href="http://www.cprogramming.com/reference/typecasting/constcast.html" rel="ugc">http://www.cprogramming.com/reference/typecasting/constcast.html</a>
</div>


I don't knw which of the parameters the compiler complains about (since all input parameters to 'strstr()' usually are 'const char*'), but maybe a 'const_cast<char*>()' can help, see http://www.cprogramming.com/reference/typecasting/constcast.html [http://www.cprogramming.com/reference/typecasting/constcast.html]

<div>
I don't think the problem is with what strstr is expecting, I think the issue is just with the part...<br />
<br />

<pre><code id="code-20-37727347-1">CStr()+uStartIndex</code></pre>
<br />
What are you trying to achieve with this? It doesn't really make sense.
</div>


I don't think the problem is with what strstr is expecting, I think the issue is just with the part...



CStr()+uStartIndex


What are you trying to achieve with this? It doesn't really make sense.

<div>
Hi infinity08,<br />
<br />
Yes it compiles like you suggested, I just have one question is :<br />
<br />
this is the rest of the code , is that safe to convert it to const char* :<br />
<br />
&nbsp;if (pszFind != NULL)<br />
&nbsp; &nbsp; {<br />
&nbsp; &nbsp; &nbsp; &nbsp; uIndex = pszFind - CStr();<br />
&nbsp; &nbsp; }
</div>


Hi infinity08,

Yes it compiles like you suggested, I just have one question is :

this is the rest of the code , is that safe to convert it to const char* :

 if (pszFind != NULL)
    {
        uIndex = pszFind - CStr();
    }

<div>
If uIndex is a const char*, that should be ok, yes.
</div>


If uIndex is a const char*, that should be ok, yes.

<div>
<div class="content wysiwyg-content">
Hi Experts,<br />
<br />
<br />
&nbsp;char* pszFind = strstr(CStr()+uStartIndex,<wbr /> pSzSearch);<br />
<br />
I got the following error :<br />
<br />
cannot convert from 'const char *' to 'char *'<br />
<br />
I need help tp resolve this problem ?<br />
<br />
Thanks,
</div>
</div>


Hi Experts,


 char* pszFind = strstr(CStr()+uStartIndex, pSzSearch);

I got the following error :

cannot convert from 'const char *' to 'char *'

I need help tp resolve this problem ?

Thanks,

'const char *' to 'char *'

C++ is an intermediate-level general-purpose programming language, not to be confused with C or C#. It was developed as a set of extensions to the C programming language to improve type-safety and add support for automatic resource management, object-orientation, generic programming, and exception handling, among other features.

C is a general-purpose, imperative computer programming language, supporting structured programming, lexical variable scope and recursion, while a static type system prevents many unintended operations. By design, C provides constructs that map efficiently to typical machine instructions, so it has found lasting use in applications that had formerly been coded in assembly language, including operating systems as well as various application software for computers ranging from supercomputers to embedded systems. It is distinct from C++ (which has its roots in C) and C#, and many later languages have borrowed directly or indirectly from C.