Java Collections sort by name - syntax error

Hi experts,

I have a problem using List, Collections.sort() <== got a syntax error

I have a List of data like below:

         SchoolContactInfo schoolContactInfo [] = {
                  new ArtStudent("Paul", "987654561"),
                  new ArtStudent("Avie", "987654561"),
                  new MathsStudent("John","98769832")};

         List<SchoolContactInfo > mylist = new ArrayList<SchoolContactInfo >();
         mylist.add(schoolContactInfo [0]);
         mylist.add(schoolContactInfo [1]);
         mylist.add(schoolContactInfo [2]);

                    Collections.sort(mylist);

What I want the output sorted by name using Collections sort but i got sysntax saying

SchoolContactInfo is not valid substitute of bounded parameters

My other class like below:

public abstract class SchoolContactInfo {
      private String name;
      private String phone;

      // Constructor
      public ContactInfo(String Name, String Phone) {
            name = Name;
            phone = Phone;
      }

      public String getName() {
            return name;
      }

      public void setName(String name) {
            this.name = name;
      }

      public String getPhone() {
            return phone;
      }

      public void setPhone(String phone) {
            this.phone = phone;
      }
}

public class ArtStudent extends SchoolContactInfo {
      // constructor
      public FriendA(String name, String phone) {
            super(name, phone);
      }
}

public class MathsStudent extends SchoolContactInfo {
      // constructor
      public FriendA(String name, String phone) {
            super(name, phone);
      }
}

===
please correct my syntax. notes i want the output of student sorted by the name
unistudentAsked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

for_yanCommented:
You class
SchoolContactInfo

should implement Comparabale interface
0
for_yanCommented:
this compiles without any error:

import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

public class School {

    public static void main(String[] args) {

          SchoolContactInfo schoolContactInfo [] = {
                  new ArtStudent("Paul", "987654561"),
                  new ArtStudent("Avie", "987654561"),
                  new MathsStudent("John","98769832")};

         ArrayList<SchoolContactInfo > mylist = new ArrayList<SchoolContactInfo >();
         mylist.add(schoolContactInfo [0]);
         mylist.add(schoolContactInfo [1]);
         mylist.add(schoolContactInfo [2]);

                    Collections.sort(mylist);

        
    }


}


  abstract class SchoolContactInfo implements Comparable <SchoolContactInfo>{
      private String name;
      private String phone;

      // Constructor
      public SchoolContactInfo(String Name, String Phone) {
            name = Name;
            phone = Phone;
      }

      public String getName() {
            return name;
      }

      public void setName(String name) {
            this.name = name;
      }

      public String getPhone() {
            return phone;
      }

      public void setPhone(String phone) {
            this.phone = phone;
      }
      
     public  int compareTo(SchoolContactInfo s){
         
         return s.getName().compareTo(name);
          
      }
}

 class ArtStudent extends SchoolContactInfo {
      // constructor
      public ArtStudent(String name, String phone) {
            super(name, phone);
      }
}

 class MathsStudent extends SchoolContactInfo {
      // constructor
      public MathsStudent(String name, String phone) {
            super(name, phone);
      }
}

Open in new window

0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
for_yanCommented:
You also hneed to keep in mind that if you define constructor - it should have the same name as the class:

public class ArtStudent extends SchoolContactInfo {
      // constructor
      public FriendA(String name, String phone) {
            super(name, phone);
      }
}

Open in new window


this acuses erroer as you "contructor" has name FriendA ()
different form the name of the class ArtStudent - this causes compilatuion error - i corrected this in the code above
0
unistudentAuthor Commented:
so clear. excellent. i am glad he helps me.
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Java

From novice to tech pro — start learning today.