Solved

Mysql select all companies when all groups are true

Posted on 2012-03-16
6
243 Views
Last Modified: 2012-03-16
Hello,

I have the following 2 tables (I simplified it here):

Customer:
`cust_id` int(10) unsigned NOT NULL auto_increment
 `cust_name` varchar(100) default NULL

Customer_groups  -> a customer can belong to many groups at the same time
`cust_id` int(10) unsigned NOT NULL
`group_id` int(10) unsigned NOT NULL

I need to select those customers who belong to ALL the selected groups.

For example let's say that the Customer_groups would have:

cust_id                   group_id
1                                   1
1                                   2
2                                   1
2                                   2
2                                   3
3                                    3
3                                    4
4                                    12
5                                      1
5                                      2
5                                      3
5                                      9
6                                       9

I want to select only those customers who belongs to group 1, group 2 and group 3.

So the result would be: customer 2 and customer 5.

How can I make such a query?

Thank you
0
Comment
Question by:starhu
  • 4
6 Comments
 
LVL 10

Expert Comment

by:Mez4343
Comment Utility
Based on your sample data the result would be Customers 1,2,3 and 5 since they belong to groups(1,2 or 3). I assume you only want the query result to return the Cust_id if the cust is in the list of groups, so added the distinct keyword. Try this


SELECT DISTINCT customer
FROM Customer a,  Customer_groups b
WHERE a.cust_id = b.cust_id
AND b.group_Id in (1,2,3)
0
 
LVL 51

Expert Comment

by:HainKurt
Comment Utility
try this:

SELECT * 
FROM   customer 
WHERE  cust_id IN (SELECT cust_id 
                   FROM   customer_groups 
                   WHERE  group_id IN ( 1, 2, 3 ) 
                   GROUP  BY cust_id 
                   HAVING COUNT(1) = 3) 

Open in new window


if it works we can write a better performing query with joins instead of using "in"
0
 
LVL 51

Expert Comment

by:HainKurt
Comment Utility
like this

SELECT c.* 
FROM   customer c 
       INNER JOIN (SELECT cust_id 
                   FROM   customer_groups 
                   WHERE  group_id IN ( 1, 2, 3 ) 
                   GROUP  BY cust_id 
                   HAVING COUNT(1) = 3) cg 
         ON cg.cust_id = cg.cust_id 

Open in new window

0
Control application downtime with dependency maps

Visualize the interdependencies between application components better with Applications Manager's automated application discovery and dependency mapping feature. Resolve performance issues faster by quickly isolating problematic components.

 
LVL 51

Expert Comment

by:HainKurt
Comment Utility
oops, my solutions are to find customers who belongs to ALL not ANY :)

just remove HAVING COUNT(1) = 3 from above query

SELECT c.* 
FROM   customer c 
       INNER JOIN (SELECT cust_id 
                   FROM   customer_groups 
                   WHERE  group_id IN ( 1, 2, 3 ) 
                   GROUP  BY cust_id) cg 
         ON cg.cust_id = cg.cust_id 

Open in new window


or

SELECT c.* 
FROM   customer c 
       INNER JOIN (SELECT unique cust_id 
                   FROM   customer_groups 
                   WHERE  group_id IN ( 1, 2, 3 )) cg 
         ON cg.cust_id = cg.cust_id 

Open in new window

0
 

Author Comment

by:starhu
Comment Utility
This works :

SELECT c.* 
FROM   customer c 
       INNER JOIN (SELECT cust_id 
                   FROM   customer_groups 
                   WHERE  group_id IN ( 1, 2, 3 ) 
                   GROUP  BY cust_id 
                   HAVING COUNT(1) = 3) cg 
         ON cg.cust_id = cg.cust_id 
                                            

Open in new window


... but can you somehow transform the select in such a form:
SELECT c.*
FROM   customer c
 where ....

The  customer table is an editable data grid in a Windows application, and the commercial Mysql plugin behaves erratically when there is a join in the select (the internal update mechanism will try to update the other table as well).

Thank you in advance
0
 
LVL 51

Accepted Solution

by:
HainKurt earned 500 total points
Comment Utility
try

SELECT c.*
FROM   customer c  where cust_id in
(SELECT cust_id
                   FROM   customer_groups
                   WHERE  group_id IN ( 1, 2, 3 )
                   GROUP  BY cust_id
                   HAVING COUNT(1) = 3)

for "in ALL GROUPS" or

SELECT c.*
FROM   customer c  where cust_id in
(SELECT unique cust_id
                   FROM   customer_groups
                   WHERE  group_id IN ( 1, 2, 3 )
)

for "in ANY GROUPS"
0

Featured Post

Backup Your Microsoft Windows Server®

Backup all your Microsoft Windows Server – on-premises, in remote locations, in private and hybrid clouds. Your entire Windows Server will be backed up in one easy step with patented, block-level disk imaging. We achieve RTOs (recovery time objectives) as low as 15 seconds.

Join & Write a Comment

A lot of articles have been written on splitting mysqldump and grabbing the required tables. A long while back, when Shlomi (http://code.openark.org/blog/mysql/on-restoring-a-single-table-from-mysqldump) had suggested a “sed” way, I actually shell …
Introduction In this article, I will by showing a nice little trick for MySQL similar to that of my previous EE Article for SQLite (http://www.sqlite.org/), A SQLite Tidbit: Quick Numbers Table Generation (http://www.experts-exchange.com/A_3570.htm…
It is a freely distributed piece of software for such tasks as photo retouching, image composition and image authoring. It works on many operating systems, in many languages.
When you create an app prototype with Adobe XD, you can insert system screens -- sharing or Control Center, for example -- with just a few clicks. This video shows you how. You can take the full course on Experts Exchange at http://bit.ly/XDcourse.

744 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

18 Experts available now in Live!

Get 1:1 Help Now