Pruning a log with Perl one-liner

Can someone give me a Perl one-liner that will go through a log and delete all lines which match a certain regex?  I'm running this on Solaris, btw.

For instance, given the content below:

this is one line
this is two lines 2011
this is three lines 2011
this is four lines

If the regex is 2011, I would like to have the file only contain:

this is one line
this is four lines


I would like to try to do this without writing to a temp file if possible.

Thanks,
David
LVL 1
David AldridgeAsked:
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David AldridgeAuthor Commented:
I was hoping to use some version of this one-liner have a ksh script wrapped around.


#!/bin/ksh
# SCRIPT: sandr
# AUTHOR: David
# DATE:   02/13/12
# REV:    1.0.T
#
# PLATFORM: Solaris
#
# PURPOSE: Search and replace. Provide a search string, replace string
#          and filename. It will replace all instances of the search
#          string with the replace string in the file passed to it. The
#          syntax is:  sandr <search string> <replace string> <filename>
#

if [ "$#" -ne 3 ]
then
        echo "\nIncorrect usage. Wrong number of arguments."
        echo "SYNTAX: <search term> <replace term> <filename>\n"
        exit 1;
else
        SEARCH=$1
        REPLACE=$2
        FILE=$3


        perl -pi -e "s/$SEARCH/$REPLACE/g" "$FILE"
        exit 0;
fi
0
ozoCommented:
perl -ni -e "print unless /$SEARCH/" "$FILE"
0

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David AldridgeAuthor Commented:
Sweet... thanks ozo.
0
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