Days in Month function embedded in query

I have a table that has budgeted values with Year/Month values. I need to get the daily values by dividing the monthly amounts by the days in the month.

Her is a sample of the data
YearMonth      BudgetMthAmtGas
2012/01      2427641
2012/02      2249955
2012/03      2382530
2012/04      2284998
2012/05      2340656

I would not think this would be all that hard but I need some help.
LVL 2
bbaldwinAsked:
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bbaldwinAuthor Commented:
Figured out how to get it done without using a function.

select case when Right([YearMonth],2) in ('01', '03', '05', '07', '08', '10', '12') then 31
                  WHEN Right([YearMonth],2) IN ('04', '06', '09', '11') THEN 30
                        ELSE CASE WHEN (YEAR(convert(DATETIME,[YearMonth]+'/01')) % 4    = 0 AND
                                YEAR(convert(DATETIME,[YearMonth]+'/01')) % 100 != 0) OR
                               (YEAR(convert(DATETIME,[YearMonth]+'/01')) % 400  = 0)
                          THEN 29
                          ELSE 28
                END
            END as DaysInMonth
from cust_team_budget
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Microsoft SQL Server

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