oracle date- finding elapsed time

that will actually support up to 999 hours

TO_CHAR(FLOOR((SYSDATE-BLEED_END_TIME)*24),'FM009')||':'||TO_CHAR(ROUND(MOD((SYSDATE-BLEED_END_TIME)*24,1)*60),'FM09')

####:20

I dont think this is right.

select to_char(floor((sysdate -bleed_end_time)*24),'fm009') || ':'
|| to_char(round(mod((sysdate -bleed_end_time)*24,1) * 60),'fm09')
from units@qlab  
 where unit_id = 'W039712003902'

---------------
120:24

I think we are in the right direction.
Thanks,

select to_char(floor((sysdate -bleed_end_time)*24),'fm009') || ':' || to_char(round(mod((sysdate -bleed_end_time)*24,1) * 60),'fm09')
from units@qlab  
 where unit_id = 'W039712003902'

120:33
 
select (sysdate - bleed_end_time)
from units@qlab  
where unit_id = 'W039712003902'  


5.02341435185185

      select to_char(trunc(sysdate)+ 5.02341435185185,'hh24:mi')
 from dual;

00:33

Here I need to get that 120:33

I think I am good with the previous solution. Instead of converting further, I am diplaying the first value of 120:33 . Will make further tests and let you know. Thanks.

####:20  --- this means the result was 4 digits, i.e.  > 999 hours

if you need to display a results that large
change

this:   to_char(floor((sysdate -bleed_end_time)*24),'fm009')


to:   to_char(floor((sysdate -bleed_end_time)*24),'fm0009')

you can keep adding 0s to the format to expand as needed.



I'm not sure what you were trying to say in http:#a37739663

thanks