Would runnng dbcc showcontig lockup table?

I have a huge table, maybe 200 million rows, no clustered index.  I want to see the fragmentation on it by running dbcc showcontig. Should I be doing this off hours? would it lock up that table? This is SQL Server 2000
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CamilliaAsked:
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gpizzutoCommented:
try to use the option "FAST". Or, better, use sys.dm_db_index_physical_stats (but don't know if it works in Sql 2000), with the "LIMITED" option.
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CamilliaAuthor Commented:
so it would lock up the table? this is sql 2000, what is "FAST" and i know it doesnt have that sys.dm_db_index_physical
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gpizzutoCommented:
This is the sintax of dbcc showcontig:

DBCC SHOWCONTIG
[ (
    { table_name | table_id | view_name | view_id }
    [ , index_name | index_id ]
) ]
    [ WITH
        {
         [ , [ ALL_INDEXES ] ]
         [ , [ TABLERESULTS ] ]
         [ , [ FAST ] ]
         [ , [ ALL_LEVELS ] ]
         [ NO_INFOMSGS ]
         }
    ]

as stated in MS documentation:

[...] The operation only requires an intent-shared (IS) table lock. This way all updates and inserts can be performed, except those that require an exclusive (X) table lock. This allows for a tradeoff between speed of execution and no reduction in concurrency against the number of statistics returned. However, if the command is being used only to gauge fragmentation, we recommend using the WITH FAST option for optimal performance. [...]
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CamilliaAuthor Commented:
so it locks the table.
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