Solved

Days between transactions when the date is stored in the same column

Posted on 2012-03-20
3
212 Views
Last Modified: 2012-06-11
I have a table (tblAnimalServices) with several columns, but the 3 I am interested in are AnimalID, ServiceDate, ServiceType.  I need to be able to find out how many days are between two different ServiceTypes for one AnimalID.  So for example the table might look like this

Animal ID         ServiceType                        ServiceDate
123456             Intake-Owner Release         01/01/12
123456             Adopted                               01/05/12
123456             Intake-Adoption Return      01/08/12

I need to find out how many days are between the Adopted and Intake-Adoption Return ServiceType for AnimalID 123456
0
Comment
Question by:animallover
  • 2
3 Comments
 
LVL 44

Expert Comment

by:GRayL
ID: 37745431
You don't care about days between Intake-Owner Release and Adopted?
0
 
LVL 77

Expert Comment

by:peter57r
ID: 37746494
Use a function as to calculate the differences.

You need to check all field names and table names...

Function NextDateDiff(Id As Long, SDate As Date) As Integer
Dim db As Database
Dim rs As DAO.Recordset
Dim strsql
'NextDateDiff = 0
Set db = CurrentDb
strsql = "Select top 1 ServiceDate from tblAnimalServices where Animalid=" & Id & " and ServiceDate >#" & Format(SDate, "yyyy-mm-dd") & "# order by Servicedate Asc"
Set rs = db.OpenRecordset(strsql)
If rs.RecordCount = 0 Then
NextDateDiff = 0
Else
NextDateDiff = rs!Servicedate - SDate
End If
rs.Close
Set rs = Nothing
Set db = Nothing

End Function

In a query based on the table add an extra column with field set to :
Interval:NextDateDiff([AnimalID], [ServiceDate])
0
 
LVL 44

Accepted Solution

by:
GRayL earned 500 total points
ID: 37749266
I have removed the space from AnimalID to make is consistent with your naming and am assuming AnimalID is numeric.  This will provide the date difference for the animal id requested.  If you want to see the date difference for all the AnimalID's , simply remove 'and AnimalID = 123456' from the last line.

SELECT a.AnimalID, a. ServiceType, a.ServiceDate
(SELECT b.ServiceDate FROM myTable b WHERE b.ServiceType = "Intake-Adoption Return"
AND b.AnimalID = a.AnimalID) AS IARServiceDate
DateDiff("d",a.ServiceDate, IARServiceDate) as ReqdDateDiff
FROM myTable a WHERE a.ServiceType = "Adopted" and AnimalID = 123456;

If AnimalID is String, wrap it in quotes.
0

Featured Post

Do You Know the 4 Main Threat Actor Types?

Do you know the main threat actor types? Most attackers fall into one of four categories, each with their own favored tactics, techniques, and procedures.

Join & Write a Comment

In a multiple monitor setup, if you don't want to use AutoCenter to position your popup forms, you have a problem: where will they appear?  Sometimes you may have an additional problem: where the devil did they go?  If you last had a popup form open…
Overview: This article:       (a) explains one principle method to cross-reference invoice items in Quickbooks®       (b) explores the reasons one might need to cross-reference invoice items       (c) provides a sample process for creating a M…
With Microsoft Access, learn how to start a database in different ways and produce different start-up actions allowing you to use a single database to perform multiple tasks. Specify a start-up form through options: Specify an Autoexec macro: Us…
Access reports are powerful and flexible. Learn how to create a query and then a grouped report using the wizard. Modify the report design after the wizard is done to make it look better. There will be another video to explain how to put the final p…

747 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

10 Experts available now in Live!

Get 1:1 Help Now