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JQuery Drop Down Menu

Posted on 2012-03-20
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Last Modified: 2012-03-20
Hi,
I have a drop down menu with the following options in my HTML;

<select name="industry" id="industry" type="select">
<option value="" selected>Please select you industry:</option>
<option value="Agricultural">Agricultural</option>
<option value="Mining">Mining</option>
<option value="Industrial">Industrial</option>
<option value="Environmental">Environmental</option>
</select>

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Now based on what the user selects, div's show and hide more form fields.
I have the menu working when the user selects either Agricultural or Mining.
Mining, Industrial and Environmental all display the same content so i was wondering how to write the statement in javascript if i wanted something like the below

if ($(this).val() == "Mining or Industrial or Environmental")

Below is the full code I'm using for the jquery menu.
I don't know much about java so any help would be apprieciated, thanks!

<script type="text/javascript">
$(document).ready(function() { $("#industry").change(function() { if ($(this).val() == "Agricultural") { $("#hide1").slideDown("fast"); } else { $("#hide1").slideUp("fast"); } } );

$("#industry").change(function() { if ($(this).val() == "Mining") { $("#hide2").slideDown("fast"); } else { $("#hide2").slideUp("fast"); } }); });
</script>

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Question by:JiveMedia
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1 Comment
 
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Accepted Solution

by:
leakim971 earned 2000 total points
ID: 37745637
something like : http://jsfiddle.net/JM4dr/1/
$(document).ready(function() { 
    $("#industry").change(function() { 
        if ($(this).val() == "Agricultural") {
            $("#hide1").slideDown("fast");
        }
        else {
            $("#hide1").slideUp("fast");
        }
        if ($(this).val() == "Mining" || $(this).val() == "Industrial" || $(this).val() == "Environmental" ) { 
            $("#hide2").slideDown("fast"); 
        }
        else {
            $("#hide2").slideUp("fast");
        }
    });
});

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¿
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