Help counting distinct Records

Posted on 2012-03-21
Last Modified: 2012-08-14
Hi I have an excel table that looks something like this

ColA ColB
==== ====
1111 10-2011
1111 10-2011
2222 10-2011
2222 10-2011
3333 10-2011
2222 11-2011
1111 11-2011
2222 11-2011
4444 11-2011
1111 11-2011
2222 11-2011
3333 12-2011
3333 12-2011
2222 12-2011
6666 12-2011
1111 12-2011
1111 12-2011
3333 12-2011

Open in new window

What I need to do is could the distinct values in A for each grouping of B

So the out put needs to look like

10-2011 3
11-2011 3
12-2011 4

Open in new window

Any ideas how I can accomplish this in Excel 2003?

Question by:PCCUtech
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Expert Comment

ID: 37749421
I think you are looking for the "Subtotal" functionality.  I have attached a screenshot on the configuration window.  Just highlight the two columns and click on the "Subtotal" icon in your toolbar.  I am running a later version of Excel, so your screen might look slightly different.

Author Comment

ID: 37749539
@netjgrnaut:  Been there and that won't help because, as an example, 1111 needs to be considered unique 3 times (1 for each different bucket in column B)

@yawkey13: I don't see a subtotal icon in my tool bars.  I am using excel 2003 and just have the "subtotal" icon.  Nor do I find that in any of the other tool bars.  Perhaps you are using a different version of excel or have a specific add-in enabled?
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Accepted Solution

barry houdini earned 500 total points
ID: 37749550
Assuming you have the first month (10-2011) in D2 you can use this "array formula" in E2


confirm with CTRL+SHIFT+ENTER and copy down

That works for any type of data in column A, if it will always be numeric data in that column then you can simplify to


also confirmed with CTRL+SHIFT+ENTER

regards, barry

Edit: example now attached

Expert Comment

ID: 37749726

Author Closing Comment

ID: 37749739
Exactly what I was looking for... had to change it a bit for my exact sheet but this is it.

I completely suck at array formulas LOL>


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