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if then statement for first record of a group <> last record of the previous group?

How to create an if then statement for first record of a group <> last record of the previous group?  this refers to group #2
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kgittinger
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kgittinger
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1 Solution
 
mlmccCommented:
Do you have a group in the report?
If so there is no real need for this test.

Test should be

If (OnFirstRecord OR {YourField} <> Previous({YourField}) then
    Do something with the first record of the group


mlmcc
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kgittingerAuthor Commented:
I have tried this
if not onFirstrecord and {Table.employee_number} <> previous({Table.employee_number}) then 1 else 0
 but if the employee_number is the same as the last employee_number of the previous group it returns a 0

I do not know how to call the group...

Please know, group 1 is employer, group 2 is class.  Employees can be in multiple classes

Thank you very much.
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mlmccCommented:
You can't call the group as such.
You put the formula on the report and at that point you have the current record and the previous record.

WHat are you trying to accomplish with this?

mlmcc
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kgittingerAuthor Commented:
I need a listing of employees (of which could be in the same plan/class for multiple  occurances), but I only want to count them once.  I cannot use distinct count because the cross-tab does not add distinct count of groups...

Here is my entire formla for counting employees

if onFirstrecord
then 1 else
if not onFirstrecord and {Table.employee_number} <> previous({Table.employee_number}) then 1 else 0

is there an first record of group(2) as opposed to OnFirstRecord?

Thank you.
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mlmccCommented:
YOu can use DISTINCTCOUNT as a summary of the employee field

If you have this as the data

employer    Class    employee    yourformula
emp1          class 1    joe                 1    
emp1           class1    tom                1
emp1           class2     joe                 1                           joe is not the previous
emp1           class3     joe                 0                           joe is the previous

Right click the employee field
Click INSERT --> SUMMARY
Change to DISTINCTCOUNT
Put it in the employer group footer

mlmcc
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kgittingerAuthor Commented:
Thanks a million!
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