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# Remove text at the beginning and end of a field with a non-standard middle

Posted on 2012-03-22
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I'm working on a report that needs to make use of a field that contains the following text:

CTMR 7.3   John Smith                   212845
CTMR 2.2   Jane Smith                   212845
GRPV 7.3   John Doe                   212845
MEMP 2.2   Jane Doe                   212845

The only part of this field I need is the first and last names in the middle but they are of non-standard length and vary with every employee.  The text to the left of the name is a system environment and the numbers are the far right are an identifier unique to them.

How would I go about stripping this field down to just say John Smith, etc?

Thanks in advance for any assistance you can provide,

~SPAR
0
Question by:StrawsPulledAtRandom
• 2

LVL 100

Assisted Solution

mlmcc earned 167 total points
Assuming you always have

XXXX XXX First Last     XXXXXXX

The X's can be any length for this to work, just need to ensure there is 1 space between the pieces.

Local StringVar Array TextList;
TextList := Split({YourFIeld},' ');
TextList[3] & ' ' & TextList[4]

If the spacing is not fixed then another approach will be needed
XXXX XXX First Last     XXXXXXX
XXXXXX XXX First Last     XXXXXXX
XXXX XXXXX First Last     XXXXXXX

All those work.  However
XXXX   XXX First Last     XXXXXXX
XXXX XXX   First Last     XXXXXXX

Will require other methods.

mlmcc
0

LVL 51

Assisted Solution

HainKurt earned 333 total points
maybe this work for you:

create a function like this:

``````ALTER FUNCTION dbo.SplitN(@String varchar(8000), @Delimiter char(1))
returns @temptable TABLE (n int, item varchar(8000))
as
begin
declare @ix int = 0;
declare @idx int = 1;
declare @slice varchar(8000);

if len(@String)<1 or @String is null  return;

while @idx!= 0
begin
set @idx = charindex(@Delimiter,@String)
if @idx!=0
set @slice = left(@String,@idx - 1);
else
set @slice = @String;

if(len(@slice)>0)
begin
set @ix=@ix+1;
insert into @temptable(n,Item) values(@ix, @slice);
end;

set @String = right(@String,len(@String) - @idx);
if len(@String) = 0 break;
end
return
end
``````

based on the code: http://blog.logiclabz.com/sql-server/split-function-in-sql-server-to-break-comma-separated-strings-into-table.aspx

then use this

``````with t as (
select 'CTMR 7.3   John Smith                   212845' data
union select 'CTMR 2.2   Jane Smith                   212845'
union select 'GRPV 7.3   John Doe                   212845'
union select 'MEMP 2.2   Jane Doe                   212845'
)
select
(select item from dbo.splitn(data, ' ') where n=3) + ' ' + (select item from dbo.splitn(data, ' ') where n=4) FullName
from t

FullName
John Smith
Jane Smith
John Doe
Jane Doe
``````
0

LVL 51

Accepted Solution

HainKurt earned 333 total points
or we can create another function based on above function

``````create function SplitNGetN(@String varchar(8000), @Delimiter char(1), @ix int =1) returns varchar(8000) as
begin
declare @result varchar(8000) = '';
set @result = (select item from dbo.splitn(@String, @Delimiter) where n=@ix)
return @result;
end;
``````

this function uses the function @ previous post

then our code will be much beautiful :)

``````with t as (
select 'CTMR 7.3   John Smith                   212845' data
union select 'CTMR 2.2   Jane Smith                   212845'
union select 'GRPV 7.3   John Doe                   212845'
union select 'MEMP 2.2   Jane Doe                   212845'
)
select dbo.SplitNGetN(data, ' ', 3) + ' ' + dbo.SplitNGetN(data, ' ', 4) FullName from t

FullName
Jane Smith
John Smith
John Doe
Jane Doe
``````
0

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