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two dimesnional Array to arraylist

Posted on 2012-03-23
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Last Modified: 2012-06-27
I wrote the below program and I got an output with which I don't want...


public class test {
public static void main(String args[]){
      int[][] providerAndYr = new int[15][2];
      int idx = 0;      
      int providerId = 0;
      int IncentiveYr = 0;
      for(int i =0; i<8; i++){
            providerAndYr[idx][0] = i;
            providerAndYr[idx++][1] = i+1;                                          
      }
      for(int j=0; j<providerAndYr.length; j++) {
            providerId = providerAndYr[j][0];
            IncentiveYr = providerAndYr[j][1];
            System.out.println("updating for provider=" + providerId);
      }      
}
}



output:
updating for provider=0
updating for provider=1
updating for provider=2
updating for provider=3
updating for provider=4
updating for provider=5
updating for provider=6
updating for provider=7
updating for provider=0
updating for provider=0
updating for provider=0
updating for provider=0
updating for provider=0
updating for provider=0
updating for provider=0

Question:

I want to avoid "updating for provider=0" I know I am getting those because I am using
for(int j=0; j<providerAndYr.length; j++) if I had used for(int j=0; j<idx; j++) my problem is solved but
I want to use the below part of code in another class and I don't want to pass temporary variable (idx) to it..is there any other way...to do it...

for(int j=0; j<providerAndYr.length; j++) {
            providerId = providerAndYr[j][0];
            IncentiveYr = providerAndYr[j][1];
            System.out.println("updating for provider=" + providerId);
      }
0
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Question by:shragi
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4 Comments
 

Author Comment

by:shragi
ID: 37757260
for(int i =0; i<8; i++){
            providerAndYr[idx][0] = i;
            providerAndYr[idx++][1] = i+1;                                          
      }


In this part of code the value 8 is not fixed...I used it as an example... to explain my problem .... it may vary if it is fixed i would have declared my array with size 8 instead of 8....
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LVL 7

Expert Comment

by:gudii9
ID: 37757343
0
 
LVL 47

Accepted Solution

by:
for_yan earned 500 total points
ID: 37757424
sorry don't understadn your problem ;
if uyou want to avoid updating for provodeId 0, why not to skip it:

for(int j=0; j<providerAndYr.length; j++) {
            providerId = providerAndYr[j][0];
if(providerId == 0)continue;
            IncentiveYr = providerAndYr[j][1];
            System.out.println("updating for provider=" + providerId);
      }

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LVL 86

Expert Comment

by:CEHJ
ID: 37757443
I know I am getting those because I am using
for(int j=0; j<providerAndYr.length; j++)

No - the reason you're getting that is that you only partially initialized 'providerAndYr' in the first loop by using a counter with a value lower than the length of the array
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