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one interface implementing another

Posted on 2012-03-23
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Last Modified: 2012-06-27
I want to have the two interfaces below.

public interface IWriteable<T>
                where T : class
{
    void Add(T newEntity);
    void Remove(T entity);
}

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public interface IReadable<T>
            where T : class
{
    IQueryable<T> FindAll();
    IQueryable<T> FindWhere(Expression<Func<T, bool>> predicate);
    T FindById(int id);
    T FindById(Guid id);
}

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Basically I want to control certain elements of different aspects of my website.

So some repositories will only be able to read certain classes, some read/write.

What I want though is for IWriteable to also Implement IReadable as my attitude is if something has the permission to write it is ok to read.

Using my interface above how to I make Iwritebale implement IReadabale?
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Question by:scm0sml
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3 Comments
 
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Accepted Solution

by:
käµfm³d   👽 earned 500 total points
ID: 37757358
Interfaces cannot provide implementation details, but you can certainly mark you IWriteable as "implementing" (only word I could think of, sorry) the IReadable interface, whose implementation responsibilities would also be passed along to classes implementing IWriteable. You simply need to note it in the implementation list (again, sorry). For example:

public interface IWriteable<T> : IReadable<T>
                where T : class
...

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Author Comment

by:scm0sml
ID: 37757381
Thats exactly what I was after thanks!

Probably didint explain myself very well!
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LVL 75

Expert Comment

by:käµfm³d 👽
ID: 37757389
Probably didint explain myself very well!
I'd say you explained it just fine  = )

Glad to help!
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