Solved

access string: replace zeros

Posted on 2012-03-23
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Last Modified: 2012-03-29
i have a field with a number of entries like




S202.005 and B20.0008

can i parse these to select and delete any zeros after the dota so they become

s202.5 B20.8

what would the query code be?
0
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Question by:topUKlawyer
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17 Comments
 
LVL 75
ID: 37760111
One way:


Left(YourField,InStr(1,YourField,".")) & val(Mid(YourField,InStr(1,YourField,".")+1))

Example:
Left("B20.0008",InStr(1,"B20.0008",".")) & val(Mid("B20.0008",InStr(1,"B20.0008",".")+1))
returns B20.8
0
 
LVL 50

Expert Comment

by:Gustav Brock
ID: 37760402
Another way:

strNum = Split(YourField, ".")(0) & "." & Val(Split(YourField, ".")(1))

/gustav
0
 
LVL 18

Expert Comment

by:p912s
ID: 37760896
And yet another way...

strField = Left(YourField, InStr(1, YourField, ".")) & Replace(Right(YourField, InStr(1, YourField, ".") - 2), "0", "")

HTH

Scot
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LVL 75
ID: 37761043
"the query code be?"

That implied this is in a query. So, Split() et al will not work ...

mx
0
 
LVL 30

Expert Comment

by:hnasr
ID: 37761411
'assume your field name: ss
'assume . exists in all fields, otherwise you need to check for that.

SELECT ss, left(ss,instr(ss,".")-1) & replace(ss,"0","",instr(ss,".")) AS myField FROM myTable
0
 
LVL 50

Expert Comment

by:Gustav Brock
ID: 37761603
> So, Split() .. will not work [in query]

You are right, but the Split code looks nicer!

/gustav
0
 
LVL 75
ID: 37761903
hnasr & p912s

What if the value is B20.000800999
You solution would replace ALL zeros
0
 
LVL 48

Expert Comment

by:Dale Fye (Access MVP)
ID: 37762836
Personally,  I would create a function to do this.  Complex queries like this lend themselves to functions which can be documented and include error handling.

If you put it in a function, you could use any of the ideas mentioned above.
0
 
LVL 45

Expert Comment

by:aikimark
ID: 37763555
In the following example, you would replace X with your field name.

left(x,instr(x,".")) & clng(mid(x,instr(x,".")+1))

Open in new window

0
 
LVL 75
ID: 37763625
What happens if the data is B20.000800ABC

?
0
 
LVL 30

Expert Comment

by:hnasr
ID: 37763652
This, I think,  is supposed to be a simple question, not a project to invite for further assumptions on the author's behalf.

"S202.005 and B20.0008
......
s202.5 B20.8

what would the query code be?"
0
 
LVL 75
ID: 37763662
Well, that's just two samples of data.
0
 
LVL 48

Accepted Solution

by:
Dale Fye (Access MVP) earned 500 total points
ID: 37765499
Like I said, I would use a function.  The advantage is that you can add error handling and special processing to accommodate anomalies within your data.  I've included sample code here.  In a query, you could use something like:

Select [FieldName], ReformatField([FieldName]) as Reformatted
FROM yourTable

Hope this helps
Dale


Public Function ReformatField(SomeValue As Variant) As Variant

    Dim strLeft As String, strRight As String
    Dim intCharPos As String
   
    'Check to see whether the value passed was NULL
    'and if so, return NULL
    If IsNull(SomeValue) Then
        ReformatField = Null
        Exit Function
    End If
   
    'Check to see whether there is actually a period in the string
    'If not, return the original value
    intCharPos = InStr(SomeValue, ".")
    If intCharPos = 0 Then
        ReformatField = SomeValue
        Exit Function
    End If
   
    'You could also put some error checking in here to make sure
    'that the position of the period in the string is not the
    'first or last character.
   
    'Parse the string
    strLeft = left(SomeValue, intCharPos - 1)
    strRight = Mid(SomeValue, intCharPos + 1)
   
    'Remove leading zeros from the right side of the string
    'You could do this with the Replace function, but it would
    'replace all of the zeros, even if they were after the first
    'non-zero value
    While left(strRight, 1) = "0"
        strRight = Mid(strRight, 2)
    Wend
   
    ReformatField = strLeft & "." & strRight
       
End Function
0
 

Author Comment

by:topUKlawyer
ID: 37765555
wow some big hitting stuff here:many thanks all you guys...
I appreciate the learned discussion.

Fyed: why do you use Public function rather than Function.
0
 
LVL 48

Expert Comment

by:Dale Fye (Access MVP)
ID: 37765576
Just the way I was taught, 20 years ago. Have always done it that way.

In code modules they are all defined as Public, in Form and Report modules, I generally make them private, unless I want to be able to call that function from some outside the form/report.
0
 
LVL 50

Expert Comment

by:Gustav Brock
ID: 37765663
Joe's original could handle Nulls this way:

Code: Left(YourField,InStr(1,Nz(YourField),".")) & Val(Mid(Nz(YourField),InStr(1,Nz(YourField),".")+1))

/gustav
0
 

Author Comment

by:topUKlawyer
ID: 37784563
Thanks everyone.

I havent got time to test them all but my eye was drawn to fyeds function solution which i tried and worked very well.

Also it introduced me to "while....wend" which I hadnt come across before and for those not particularly logical reasons I am awarding the points to fyed. Thanks for all replying and I may well be able to test and use your solutions in the future.
0

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