htaccess Rewrite Single Digit Wildcard

Is there a single digit wildcard that can be used with RewriteRule?  Here's an example, this is my current code:

RewriteCond %{REQUEST_URI} .*user_screenshots/14.*
RewriteRule ^(.*)user_screenshots/14(.*)$ http://%{HTTP_HOST}/$1user_screenshots/saves14/14$2 [R,L]

If # was a single digit wildcard, this is what that code would look like:

RewriteCond %{REQUEST_URI} .*user_screenshots/14###.*
RewriteRule ^(.*)user_screenshots/14###(.*)$ http://%{HTTP_HOST}/$1user_screenshots/saves14/14###$2 [R,L]

So my question is, what is the single digit wildcard that can be used in this?

Thanks.
davideo7Asked:
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designatedinitializerCommented:
mod_rewrite accepts regular expressions.
if you want to match 0 or more characters use a single question mark (?).
If you want to match a digit use a character class like this:

[0-9]

(square brackets included)
davideo7Author Commented:
designatedinitializer: What if I want a wildcard of just 3 digits?
designatedinitializerCommented:
that's 3 times the same formula:

[0-9][0-9][0-9]

Notice that this matches any 3 digits.
It won't match 2 digits, nor 1 digit, nor no digits at all.

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davideo7Author Commented:
designatedinitializer: So would it look like this?

RewriteCond %{REQUEST_URI} .*user_screenshots/14[0-9][0-9][0-9].*
RewriteRule ^(.*)user_screenshots/14[0-9][0-9][0-9](.*)$ http://%{HTTP_HOST}/$1user_screenshots/saves14/14[0-9][0-9][0-9]$2 [R,L]
designatedinitializerCommented:
yep

14[0-9][0-9][0-9]

 will match 14000 through 14999.
designatedinitializerCommented:
I was talking about the wildcard/regexp you asked about.
What exactly are you trying to acomplish?
The example you give above shows two equal strings.
davideo7Author Commented:
davideo7Author Commented:
Ok I figured it out, I had to rewrite my code like this:

RewriteCond %{REQUEST_URI} .*user_screenshots/14[0-9][0-9][0-9].*
RewriteRule ^(.*)user_screenshots/14([0-9])([0-9])([0-9])(.*)$ http://%{HTTP_HOST}/$1user_screenshots/saves14/14$2$3$4$5 [R,L]

Had to put brackets around the [0-9] and had to add $2$3$4 in there.
designatedinitializerCommented:
Hi,
Yeah, you're right.
You could also do it like this: (14[0-9][0-9][0-9])/(.*)
And then use $1$2

The brackets turn the match pattern into a group.
The $n stuff refers to the n'ths group matched back there.
davideo7Author Commented:
I was able to figure out the 2nd half of the problem on my own but designatedinitializer helped me with the first half.  Thanks.
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