code does not work inside $(document).ready(function() {

Posted on 2012-03-24
Last Modified: 2012-03-24
can some one tell me why may code does not work when I put it inside $(document).ready(function() { });
it works fine if I do not put it in there.

// JavaScript Document
$(document).ready(function() { ////makes sure document is ready before excuting any jquery  
function bizType(type)
        if(type=='MEDI') {
		if(type=='REST') {
		if(!(type=='MEDI' || type=='REST')) {

}); //// end of document ready
///End jquery

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Question by:Luey

Accepted Solution

designatedinitializer earned 500 total points
ID: 37761644
that's because you are calling the function bizType somewhere else, and that somewhere else gets executed before $(document).ready.

You actually don't need it inside $(document).ready
That's a function. It will only execute when you call it.
What you need inside $(document).ready is stuff that needs to initialize and act upon the DOM, which only exists on $(document).ready.

PS: You can convert those 3 'if' s to if(...){---} else if(...) {---} else {---}

Author Closing Comment

ID: 37761655
ok now i understand thanks

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