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For Inside ForEach Only Inserting First Array Value

Posted on 2012-03-27
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Last Modified: 2012-08-14
Hi Experts,

Thanks for reason. The code below works, excepts it only inserts the first array first with $id=1 into the database and then reports a duplicate value for 1 in the database, so it's not getting to 2 or 3. Can you help me identify why?

The database insert code is Zend and is valid. Thanks!

$info = array(
    1 => array( 5, 'Name' ),
    2 => array( 5, 'Name' ),
    3 => array( 3, 'Name 2' )
    );

foreach( $info as $id => $data )
{
    
    for( $id_value_id = 0; $id_value_id < 3; $id_value_id++ )
    {
    
        $data = array(
            'id'            => $id,
            'user_id'       => $data[0],
            'name'          => $data[1],
            );
        
        $db->insert(
            'title',
            $data
            );
        
    }
    
}

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Question by:SevenAteAnthony
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12 Comments
 
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Expert Comment

by:Beverley Portlock
Comment Utility
You are putting the original array into a variable called $data which you then overwrite in the loop.


foreach( $info as $id => $data )
{
       ....

        $data = array(
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Author Comment

by:SevenAteAnthony
Comment Utility
Thanks for finding that. I actually messed up when I renamed the variables to place on here to public eyes. Excluding that find, do you see anything else wrong with the idea behind the code why it would loop to the first one and keep looping to the first one until it reports the duplicate error?
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Expert Comment

by:gr8gonzo
Comment Utility
Is that the actual code or did you modify it at all to show on here?
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Author Comment

by:SevenAteAnthony
Comment Utility
Actual code. Variable names were modified. Thanks.
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LVL 34

Expert Comment

by:gr8gonzo
Comment Utility
How heavily modified? More specifically, what were the original variable names on each of the loop lines?
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Author Comment

by:SevenAteAnthony
Comment Utility
There's nothing wrong with the variables names minus the double $data. They were changed for legality reasons. Please assume the above are the variables names if you're willing to help. Thanks.
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Expert Comment

by:Ray Paseur
Comment Utility
Variable names that are changed for any reason have no place in the debugging process.

Please do one of the following: (1) Post the actual code, along with the CREATE TABLE statements and enough data to illustrate the issue, so we can copy it and run it on our own servers, of (2) Create a replica that exactly illustrates the problem, and post all of the actual code, CREATE TABLE statements and enough test data to load the tables and illustrate the issue.  

Good test data and access to the actual code are kind of the foundation of programming.

Thanks, ~Ray
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Accepted Solution

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SevenAteAnthony earned 0 total points
Comment Utility
You guys are being too dramatic. I figured out the issue anyway and it was that I didn't even need a for statement to access the array in the array. Just needed a quick pair of developer eyes on the code. All is fixed now.
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Expert Comment

by:gr8gonzo
Comment Utility
Well, the reason I ask is because I'm trying to figure out why you're looping 3 times with no difference in the data:

for( $id_value_id = 0; $id_value_id < 3; $id_value_id++ )
{
... query in here ...
}

You're running the same query 3 times, so I figured there may have been something changed in the variable names to explain why and maybe the original had something changing. As of right now, the only variable that changes is $id_value_id but it's never used inside your loop.

The simple fact that I'm asking should indicate that I'm willing to help. I'm just trying to figure out the problem.
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by:gr8gonzo
Comment Utility
Umm... okay... I don't think it has anything to do with being dramatic. We just don't have any information other than what you give us. Most of us are pretty experienced programmers - we don't really ask for information unless it's relevant to understanding the problem and the solution.
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Expert Comment

by:Ray Paseur
Comment Utility
Going forward, SevenAteAnthony, you'll get quicker results if you can create a test case that demonstrates the issues.  Often you will find that just the act of creating the test case will cause you to think about the issues in ways that will lead you to the solution.  The creation of a test case is a useful exercise and one worthy of your time.  Changing the variable names or obscuring the data base details is not worthy of your time.  In fact, these kinds of changes often introduce more errors into the code.  So when you're wondering what you can produce for "public eyes" try your best to isolate the issues and demonstrate them separately.  It is only easy to eat an elephant if you do it a bite at a time.
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Author Closing Comment

by:SevenAteAnthony
Comment Utility
Chosen because I fixed it myself.
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