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Java: problems with for loop? any thoughts... thx

Posted on 2012-03-27
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Last Modified: 2012-03-27
Hello Experts,

Having problems with the loop below; it may not be a loop... I am not sure...

any thoughts will help ... thx..

based on a home code; need to find all materials belonging to that house... can't get it to work... thx again

public class SearchHomeMaterials {

	public static void main(String[] args) {		
		//log source
		String source = " home s78i has featureNumber E7i10 built with material Wood " +
				"E7i10 has a kitchen, two baths, three bedrooms and bar built with material 4397 " +
				" home 67cf6 has featureNumber E2410 built with material890217 " +
				"home s78i contains a tree, chairs, and front door with material Plastic " +
				" home 65ac has featureNumber D7i10 using material4397  material Plywood " +
				"home s78i posseses a patio, closet doors, and cabinets have material Glass " +
				" home 67cf6 has featureNumber D5844 built with material 4446" +
				"D5844 has a gold window with material5643" +
				" home 33zt has featureNumber E4ty8 built with materialm111" +
				"E4ty8 has 7 doors and 3 shelves built with material Wood";	
		
		//pseudo: 1: search materials belonging to this home
		String home = "s78i";		
		String material = "material";
		
		//pseudo: 2: add materials found for house s78i to vector
		Vector<String> homeMaterials = new Vector<String>(); 	
		String logs[] = source.split("[\\s]"); 
		boolean addMaterial = false;

		for (String log : logs) {
			if (addMaterial) {
				// add material found for that house: Wood, Plastic, Glass to vector
				if(log.equals(material)){
					homeMaterials.add(log);
				}
				addMaterial = false;
			}

			// if home searched found, add material true
			if (log.equals(home)) {
				addMaterial = true;
			}
		}		
		System.out.println(homeMaterials);       
        
	}//END OF MAIN
	
}//END OF CLASS

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0
Comment
Question by:epifanio67
  • 5
  • 2
7 Comments
 
LVL 47

Expert Comment

by:for_yan
ID: 37774153
Now it prints materials:

import java.util.Vector;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class SearchHomeMaterials {

	public static void main(String[] args) {
		//log source
		String source = " home s78i has featureNumber E7i10 built with material Wood " +
				"E7i10 has a kitchen, two baths, three bedrooms and bar built with material 4397 " +
				" home 67cf6 has featureNumber E2410 built with material890217 " +
				"home s78i contains a tree, chairs, and front door with material Plastic " +
				" home 65ac has featureNumber D7i10 using material4397  material Plywood " +
				"home s78i posseses a patio, closet doors, and cabinets have material Glass " +
				" home 67cf6 has featureNumber D5844 built with material 4446" +
				"D5844 has a gold window with material5643" +
				" home 33zt has featureNumber E4ty8 built with material m111" +
				"E4ty8 has 7 doors and 3 shelves built with material Wood";

		//pseudo: 1: search materials belonging to this home
		String home = "s78i";
		String material = "material";

		//pseudo: 2: add materials found for house s78i to vector
		Vector<String> homeMaterials = new Vector<String>();

        Pattern p = Pattern.compile("material[\\s]+(\\w+)\\s");
        Matcher m = p.matcher(source);

        while(m.find()){


            System.out.println(m.group(1));
            homeMaterials.add(m.group(1));
        }


		String logs[] = source.split("material[\\s]+");
		boolean addMaterial = false;

		for (String log : logs) {
			if (addMaterial) {

                System.out.println(log);
				// add material found for that house: Wood, Plastic, Glass to vector
				if(log.equals(material)){
					homeMaterials.add(log);
				}
				addMaterial = false;
			}

			// if home searched found, add material true
			if (log.equals(home)) {
				addMaterial = true;
			}
		}
		System.out.println(homeMaterials);

	}//END OF MAIN

}//END OF CLASS

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Output:

Wood
4397
Plastic
Plywood
Glass
4446D5844
m111E4ty8
[Wood, 4397, Plastic, Plywood, Glass, 4446D5844, m111E4ty8]

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0
 
LVL 47

Expert Comment

by:for_yan
ID: 37774170
That would be better as some of them don't have space after material

import java.util.Vector;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class SearchHomeMaterials {

	public static void main(String[] args) {
		//log source
		String source = " home s78i has featureNumber E7i10 built with material Wood " +
				"E7i10 has a kitchen, two baths, three bedrooms and bar built with material 4397 " +
				" home 67cf6 has featureNumber E2410 built with material890217 " +
				"home s78i contains a tree, chairs, and front door with material Plastic " +
				" home 65ac has featureNumber D7i10 using material4397  material Plywood " +
				"home s78i posseses a patio, closet doors, and cabinets have material Glass " +
				" home 67cf6 has featureNumber D5844 built with material 4446" +
				"D5844 has a gold window with material5643" +
				" home 33zt has featureNumber E4ty8 built with materialm111" +
				"E4ty8 has 7 doors and 3 shelves built with material Wood";

		//pseudo: 1: search materials belonging to this home
		String home = "s78i";
		String material = "material";

		//pseudo: 2: add materials found for house s78i to vector
		Vector<String> homeMaterials = new Vector<String>();

        Pattern p = Pattern.compile("material[\\s]*(\\w+)\\s");
        Matcher m = p.matcher(source);

        while(m.find()){


            System.out.println(m.group(1));
            homeMaterials.add(m.group(1));
        }


		String logs[] = source.split("material[\\s]+");
		boolean addMaterial = false;

		for (String log : logs) {
			if (addMaterial) {

                System.out.println(log);
				// add material found for that house: Wood, Plastic, Glass to vector
				if(log.equals(material)){
					homeMaterials.add(log);
				}
				addMaterial = false;
			}

			// if home searched found, add material true
			if (log.equals(home)) {
				addMaterial = true;
			}
		}
		System.out.println(homeMaterials);

	}//END OF MAIN

}//END OF CLASS

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Output:

Wood
4397
890217
Plastic
4397
Plywood
Glass
4446D5844
5643
m111E4ty8
[Wood, 4397, 890217, Plastic, 4397, Plywood, Glass, 4446D5844, 5643, m111E4ty8]

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0
 

Author Comment

by:epifanio67
ID: 37774183
Thank you for_yan...
however, the solution above is printing all the materials...
I need to print all the material that belong to home s78i.... excluding the other ones... see what I am?

thx so much for your help...

regards
0
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LVL 47

Expert Comment

by:for_yan
ID: 37774185
split{) method is not very suitable for this case - you rather want t use Pattern and find pattern wehre the word material if ollowed by the next word and you want toretrieve the next word - ans dthat what it is doing now
0
 
LVL 47

Expert Comment

by:for_yan
ID: 37774208
this will do only for s78i:

import java.util.Vector;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class SearchHomeMaterials {

	public static void main(String[] args) {
		//log source
		String source = " home s78i has featureNumber E7i10 built with material Wood " +
				"E7i10 has a kitchen, two baths, three bedrooms and bar built with material 4397 " +
				" home 67cf6 has featureNumber E2410 built with material890217 " +
				"home s78i contains a tree, chairs, and front door with material Plastic " +
				" home 65ac has featureNumber D7i10 using material4397  material Plywood " +
				"home s78i posseses a patio, closet doors, and cabinets have material Glass " +
				" home 67cf6 has featureNumber D5844 built with material 4446" +
				"D5844 has a gold window with material5643" +
				" home 33zt has featureNumber E4ty8 built with materialm111" +
				"E4ty8 has 7 doors and 3 shelves built with material Wood";

		//pseudo: 1: search materials belonging to this home
		String home = "s78i";
		String material = "material";

		//pseudo: 2: add materials found for house s78i to vector
		Vector<String> homeMaterials = new Vector<String>();

        String []  homes = source.split("home");

        for(String homeS: homes) {
            if(homeS.indexOf("s78i") == -1)continue;
        Pattern p = Pattern.compile("material[\\s]*(\\w+)\\s");
        Matcher m = p.matcher(homeS);

        while(m.find()){


            System.out.println(m.group(1));
            homeMaterials.add(m.group(1));
        }

        }


		String logs[] = source.split("material[\\s]+");
		boolean addMaterial = false;

		for (String log : logs) {
			if (addMaterial) {

                System.out.println(log);
				// add material found for that house: Wood, Plastic, Glass to vector
				if(log.equals(material)){
					homeMaterials.add(log);
				}
				addMaterial = false;
			}

			// if home searched found, add material true
			if (log.equals(home)) {
				addMaterial = true;
			}
		}
		System.out.println(homeMaterials);

	}//END OF MAIN

}//END OF CLASS

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Output:
Wood
4397
Plastic
Glass
[Wood, 4397, Plastic, Glass]

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0
 
LVL 47

Accepted Solution

by:
for_yan earned 500 total points
ID: 37774218
Thsi is the same thing as above but using your variable home, rather than repeating "s78i"

import java.util.Vector;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class SearchHomeMaterials {

	public static void main(String[] args) {
		//log source
		String source = " home s78i has featureNumber E7i10 built with material Wood " +
				"E7i10 has a kitchen, two baths, three bedrooms and bar built with material 4397 " +
				" home 67cf6 has featureNumber E2410 built with material890217 " +
				"home s78i contains a tree, chairs, and front door with material Plastic " +
				" home 65ac has featureNumber D7i10 using material4397  material Plywood " +
				"home s78i posseses a patio, closet doors, and cabinets have material Glass " +
				" home 67cf6 has featureNumber D5844 built with material 4446" +
				"D5844 has a gold window with material5643" +
				" home 33zt has featureNumber E4ty8 built with materialm111" +
				"E4ty8 has 7 doors and 3 shelves built with material Wood";

		//pseudo: 1: search materials belonging to this home
		String home = "s78i";
		String material = "material";

		//pseudo: 2: add materials found for house s78i to vector
		Vector<String> homeMaterials = new Vector<String>();

        String []  homes = source.split("home");

        for(String homeS: homes) {
            if(homeS.indexOf(home) == -1)continue;
        Pattern p = Pattern.compile("material[\\s]*(\\w+)\\s");
        Matcher m = p.matcher(homeS);

        while(m.find()){


            System.out.println(m.group(1));
            homeMaterials.add(m.group(1));
        }

        }


		String logs[] = source.split("material[\\s]+");
		boolean addMaterial = false;

		for (String log : logs) {
			if (addMaterial) {

                System.out.println(log);
				// add material found for that house: Wood, Plastic, Glass to vector
				if(log.equals(material)){
					homeMaterials.add(log);
				}
				addMaterial = false;
			}

			// if home searched found, add material true
			if (log.equals(home)) {
				addMaterial = true;
			}
		}
		System.out.println(homeMaterials);

	}//END OF MAIN

}//END OF CLASS

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Wood
4397
Plastic
Glass
[Wood, 4397, Plastic, Glass]

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0
 

Author Closing Comment

by:epifanio67
ID: 37774237
thank you for_yan...
I see what you did... thank you so much....

boy, I have long way to go with Java... thx for your patience....
0

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