Java: regular expression to filter times in order, how to?

Hello Experts,

The regular expression below is not working for me... I want to filter times and order them...

any thoughts?

thx for your help...

regards,

public class RegularExpression {

	public static void main(String[] args) {
		// log source
		String source = "12:22:22.926_I_I_00 [07:48] function will be continued(0,832569404) \n" +
				"12:22:22.726_I_I_00a [09:04] <<<<<<<<<<<<suspend interpretator(JUMPING), timers:0000 \n" +
				"12:22:22.827_I_I_0 [07:49] function is continued(0,832569404) \n" +
				"12:22:22.828_I_I_00a101c1a3bb4073 [09:06] >>>>>>>>>>>>start interpretator \n " +
				"12:22:22.829 Int 22000  \n" +
				"12:22:22.830_I_I_00a1 [07:38] HERE IS XDATA \n" +
				" 12:22:22.831_I_I_0 [09:04] <<<<<<<<<<<<suspend interpretator(XDATA_EX), timers:00010 \n" +
				" 12:22:22.841_T_I_0000000000000000 [14:0c]  (this dn=Preroute) \n" +
				" 12:22:22.841_I_I_0000000000000000 [01:01] call (2984793-036846a0) for Resources created (del 490) \n" +
				" 12:22:22.931_I_I_0 [09:04] <<<<<<<<<<<<suspend interpretator(XDATA_EX), timers:00010 \n" +
				" 12:22:23.141_T_I_0000000000000000 [14:0c]  (this dn=Preroute) \n" +
				" 12:22:23.841_I_I_0000000000000000 [01:01] call (2984793-036846a0) for Resources created (del 490) \n" +
				"";

//		Vector<String> times = new Vector<String>();
		Pattern timePattern = Pattern.compile("[\\dd]*(\\p{Punct})*[\\dd]*(\\p{Punct})*[\\dd]*(\\p{Punct})*[\\ddd]");
		Matcher timeMatcher = timePattern.matcher(source);
		while (timeMatcher.find()) {
			System.out.println(timeMatcher.group());
//			times.add(m.group());
		}
		


	}// END OF MAIN

}// END OF CLASS

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epifanio67Asked:
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Terry WoodsIT GuruCommented:
Try this:
Pattern timePattern = Pattern.compile("\\d+:\\d+:\\d+\\.*\\d+");
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for_yanCommented:
But here you have each line starting with time.
You don't need regex for that make it
ByteaArrayInputStream(source.getBytes())
and then read lnes, trim() them and then so substring (0, 12) and parse it to time
using SimpleDateFormat

What do you want as the output ?
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for_yanCommented:
I think this should be more accurate, if you still want regex:

Pattern.compile("\\d{2}:\\d{2}:\\d{2}\\.\\d{3}");
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epifanio67Author Commented:
thank you experts... both regular expressions work...
for_yan, I am also going to try ByteaArrayInputStream(source.getBytes())....

thx a million...

regards
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CEHJCommented:
for_yan, I am also going to try ByteaArrayInputStream(source.getBytes())....

Don't bother - use a Scanner ;)
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