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SQL Query Help

Team -

I have a table with a field "Information" in which i would like to get only the first character of all the words.

Example:
"Information" fields contains 5 rows

1. What is my name?
2. Ohio is a nice place.
3. Oh My God !!!
4. Job Well done..,
5. Hearty Welcome to our chairman.

I'd like to run a query which will pull only the first character of each word in each row.

i.e.,
1.WIMN
2.OIANP
3.OMG
4.JWD
5.HWTOC

Requesting your help please
0
davidi1
Asked:
davidi1
1 Solution
 
Om PrakashCommented:
Try:
SELECT left(field1,1), left(field2,1) from your_table_name
0
 
BawerCommented:
select SUBSTR(first_name,1,1)name from employee
0
 
gplanaCommented:
I think there isn't any function on SQL-Server for getting first character of every word. I think you need to create a user defined function for achieving this and then execute this query:

SELECT FirstCharOfEveryWord(Information) as first_characters
FROM yourTable;

Where FirstCharOfEveryWord is the function you should create. I suppose the idea is to take the first character (by SUBSTR function) and then use a loop to treat every character (gotten also by SUBSTR) and everytime you find a space take next character. But probably you should also treat things like if there are more than one space together, what to do with punctuation signs (point, comma, ...) and things like this, so this function could not be easy.
0
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deightonCommented:
do this using a function

-- ================================================
-- Template generated from Template Explorer using:
-- Create Scalar Function (New Menu).SQL
--
-- Use the Specify Values for Template Parameters 
-- command (Ctrl-Shift-M) to fill in the parameter 
-- values below.
--
-- This block of comments will not be included in
-- the definition of the function.
-- ================================================
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
-- =============================================
-- Author:		<Author,,Name>
-- Create date: <Create Date, ,>
-- Description:	<Description, ,>
-- =============================================
CREATE  FUNCTION fn_SentenceChars
(
	-- Add the parameters for the function here
	@SENTENCE varchar(200)
)
RETURNS varchar(200)
AS
BEGIN
	-- Declare the return variable here
	DECLARE @ANS  varchar(200)




DECLARE @I int;
SET @I = 1
WHILE @I < LEN(@SENTENCE)
BEGIN
	IF @I = 1
	BEGIN
	   SET @ANS = LEFT(@SENTENCE, 1);
	END
	ELSE
	BEGIN
		IF SUBSTRING(@SENTENCE, @I - 1, 1) =' ' AND SUBSTRING(@SENTENCE, @I, 1) <> ' '
				SET @ANS = @ANS + SUBSTRING(@SENTENCE, @I, 1); 	 
	END		
	SET @I = @I + 1;
END

-- Return the result of the function
RETURN @ANS



END
GO

Open in new window



then use it on your fields, here is a test I did

select dbo.fn_SentenceChars('the cat sat on the mat')

Open in new window

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RimvisCommented:
Hi davidi1,

try this:

SELECT *, 
	(SELECT UPPER(SUBSTRING(Information, n, 1)) 
		FROM YourTable CROSS JOIN (SELECT row_number() over (order by object_id) AS n FROM sys.columns) AS num 
		WHERE ID = y.ID AND SUBSTRING(' ' + Information, n, 1) = ' ' AND n<LEN(Information) FOR XML PATH('')) 
FROM YourTable AS y

Open in new window

0
 
SJCFL-AdminCommented:
You are obviously doing this as part of another process.   I could not help wondering if you were implementing your own searching mechanism.  In which case, I would highly recommend you looked into implementing a full text index.
0
 
Scott PletcherSenior DBACommented:
>> first character of all the words. <<

You have to define what you mean by "word".

Only spaces??

Me personally, I would think something along these lines, *conceptually* (not necessarily directly coded this way):

Find the first/next alpha/numeric char, to start a "word"
All immediately following: alpha,numeric, *and underscores* are part of that "word" (./|~ etc are not)
    First char that is NOT one of those ends the "word".
--Loop/repeat until all words are processed.


Is that right?  Or do you want include other chars within a "word"?
0

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