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how to call php script in java

Posted on 2012-04-02
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Last Modified: 2012-08-13
hello - i would like to know how to call a php script from java applet.

outcome - passing java parameters to php

can you provide a working example?

thanks in advance for your help!
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Question by:only1wizard
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11 Comments
 
LVL 108

Accepted Solution

by:
Ray Paseur earned 500 total points
ID: 37796083
For something like this, I think I would set the PHP script up as a web service and call it via a RESTful interface.  Basically, the PHP script would have its own URL and you would pass the parameters to the URL as part of the query string.  This makes it easy to test the web service because you can just type the URL into a browser address bar and see the results.  See this code snippet as an example of a PHP web service.
<?php // RAY_REST_get_last_name.php
error_reporting(E_ALL);



// DEMONSTRATE HOW A RESTFUL WEB SERVICE WORKS
// INPUT FIRST NAME, OUTPUT FAMILY NAME
// CALLING EXAMPLE:
// file_get_contents('http://laprbass.com/RAY_REST_get_last_name.php?key=ABC&resp=XML&name=Ray');



// OUR DATA MODEL CONTAINS ALL THE ANSWERS - THIS COULD BE A DATA BASE - AS SIMPLE OR COMPLEX AS NEEDED
$dataModel
= array
( 'Brian'   => 'Portlock'
, 'Ray'     => 'Paseur'
, 'Richard' => 'Quadling'
, 'Dave'    => 'Baldwin'
)
;


// RESPONSE CAN BE PLAIN TEXT OR XML FORMAT
$alpha = NULL;
$omega = NULL;
if ( (isset($_GET["resp"])) && ($_GET["resp"] == 'XML') )
{
    // PREPARE THE XML WRAPPER
    $alpha = '<response>';
    $omega = '</response>';
}



// TEST THE 'API KEY' - THIS COULD BE A DATA BASE VALIDATION LOOKUP - AS SIMPLE OR COMPLEX AS NEEDED
$key = (!empty($_GET["key"])) ? $_GET["key"] : FALSE;
if ($key !== 'ABC')
{
    echo $alpha . 'BOGUS API KEY' . $omega;
    die();
}



// LOOK UP THE FAMILY NAME
$name = (!empty($_GET["name"])) ? $_GET["name"] : 'UNKNOWN';

// IF THE NAME FROM THE URL IS FOUND IN THE DATA MODEL
if (array_key_exists($name, $dataModel))
{
    // RETURNS THE APPROPRIATE FAMILY NAME FROM THE DATA MODEL
    echo $alpha . $dataModel[$name] . $omega;
    die();
}

// RETURNS THE UNKNOWN NAME INDICATOR
else
{
    echo $alpha . 'UNKNOWN' . $omega;
    die();
}

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0
 

Author Comment

by:only1wizard
ID: 37796116
do you have an example of java applet that would pass the java variable to php script?

thanks in advance for your help!
0
 
LVL 108

Expert Comment

by:Ray Paseur
ID: 37796224
No, I only have the PHP side.  Leave the question open for a while and maybe a Java programmer will come along with the other half of the solution!
0
 

Author Comment

by:only1wizard
ID: 37796245
ok will do thank u
0
 

Author Closing Comment

by:only1wizard
ID: 37800658
thanks for your example of the web service!

i have solved this problem the java works fine it was the php. solution i resolved the problem by focusing on getting the php script working alone with out the java once it ran on its own i recompiled java and ran the file and it works.

thanks in advance for your help!
0
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LVL 10

Expert Comment

by:gordon_vt02
ID: 37800663
Take a look at the java.net.URL and java.net.HttpURLConnection classes.  You should be able to use those to call the PHP web service and pass whatever parameters are required, then read the response as an InputStream in your applet.  If the PHP service is not located on the same web server, you'll have to sign your applet or you won't be able to communicate with it.

Sample use of HttpURLConnection:
public Object queryService(Object param1, Object param2) {
    String encParam1 = URLEncoder.encode(param1.toString(), "UTF-8");
    String encParam2 = URLEncoder.encode(param2.toString(), "UTF-8");
    URL serviceURL = new URL(String.format("http://www.yourserver.com/webService.php?param1=%s&param2=%s", encParam1, encParam2));
    HttpURLConnection conn = (HttpURLConnection)serviceURL.openConnection();
    // check response code -- if OK, proceed with processing output, otherwise handle errors
    int responseCode = conn.getResponseCode();
    if (responseCode == HttpURLConnection.HTTP_OK) {
        InputStream response = conn.getInputStream();
        // read from the input stream and process results appropriately
    } else {
        // check error code and take appropriate actions
    }
    conn.close();
}

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I left out the exception handling, but you'll need to account for those as well.  Mostly subclasses of IOException, but there are some others as well (MalformedURLException for one).  Hope that helps!
0
 

Author Comment

by:only1wizard
ID: 37800744
oh here is my java code

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.net.URL;
import java.net.URLConnection;

/**
 * Send a POST request using URLConnection
 * (Consider using HttpURLConnection or HttpsURLConnection)
 */

/**
 *
 * @author theodore werntz ii
 */
public class WebClientPHP {
    
public static void main(String[] args) {
        
        try {
            // Prepare data
            String data = "testData" ; // grab users session id
                              
            // Prepare connection
            URL url = new URL("http://127.0.0.1/subtest.php?name="+ data );
            URLConnection connection = url.openConnection();
            connection.setDoOutput(true);  // Needed to write to a URLConnection
            
             // Get the response
            BufferedReader reader = new BufferedReader(
                                          new InputStreamReader(
                                                connection.getInputStream()));
            // Print the response
            String line;
            while ((line = reader.readLine()) != null)
                System.out.println(line);
            
            reader.close();  // Close the reader
        }
        catch (Exception e) {
            e.printStackTrace();
        }
    }
}

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just thought i would share the java code as well

thanks in advance for your help!
0
 
LVL 10

Expert Comment

by:gordon_vt02
ID: 37801137
Make sure you URLEncode the parameter string, just in case there are any reserved characters.  Unless you are planning on pushing data to the connection, there's no need to call connection.setDoOutput(true).  That would only be necessary if you were calling connection.getOutputStream() and writing data to it.
0
 

Author Comment

by:only1wizard
ID: 37801289
can i have multiple strings i.e.

String data = <?php $_SESSION['UserName'] ?>;
String UserId = <?PHP $_SESSION['UserId'] ?>;

i will encode the params just gave that as an example.

then i will reference them i.e.

URL url = new URL("http://localhost/subtest.php?name=" + data + "&id=" +UserId);

thanks in advance for your help!
0
 
LVL 10

Expert Comment

by:gordon_vt02
ID: 37802594
Yep.  That should work.  Especially with multiple parameters, I'd recommend going the String.format() route for the URL.  Easier to read than String concatenation and more efficient as well.

URL url = new URL(String.format("http://localhost/subtest.php?name=%s&id=%s", data, UserId);

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0
 
LVL 10

Expert Comment

by:gordon_vt02
ID: 37802596
Oops... forgot the closing ) above.
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