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centos cluster on   esx5i

Posted on 2012-04-03
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Last Modified: 2012-06-27
Hi,

I want to experiment centos cluster on my esx host. Can I experiment by installing centos on 2 vm guests?
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Question by:mokkan
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Andrew Hancock (VMware vExpert / EE MVE) earned 500 total points
ID: 37801337
Yes, Centos is a supported Guest OS for VMware vSphere ESXi 5.0.

also see here

http://www.zoobey.com/index.php/resources/all-articles-list/100-configuring-a-high-availability-clus
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by:mokkan
ID: 37801435
Thank you very much it looks good.  I have a question regarding the cluster IP  addresss, basically apache is running on cluster IP(172.16.4.82)(From the example). Basically hearbeat daemon will manage the cluster IP address and will assign to node1 or node2 ?
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Author Comment

by:mokkan
ID: 37801454
How does switch know about the cluster IP address since it is not assigned to any of the physical ports on the server?
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LVL 118
ID: 37801487
The cluster IP address is the Address you use to communicate with the cluster.
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LVL 118
ID: 37801494
It's a virtual IP address.
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by:mokkan
ID: 37801533
I totally understand, but how does application knows this IP address on which node?
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LVL 118
ID: 37801568
Clustering software creates a virtual IP address, and this load balances between the two nodes in the cluster.
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by:mokkan
ID: 37801593
I understand, but it doesn't  bind with any of the interface right like eht0:1 or ... like that right? It resides in cluster  pacakge?
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LVL 118
ID: 37801637
Correct.
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Author Comment

by:mokkan
ID: 37802031
sorry still confused, how  does switch knows about this IP address? Does cluster package broadcast and register with the switch?
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LVL 118
ID: 37802049
Packets are sent to the Cluster IP Address, the Cluster software has the node1 and node2 addresses, and sends the packet to the relevant node in the cluster.

Cluster IP Address are unicast or multicast. Cluster IP address is based on a Mac Address.
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Author Comment

by:mokkan
ID: 37806096
thank you,  sorry still have question, If you ping for cluster ip address, who will return?
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