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array within an array in PHP

Hi: I have an array that counts the required number of columns and rows and generates a table, the code is attached. Now I have another date array which I need to insert within my <td> tag and I am not able to get it to work. The first date needs to be shown in "$firstCell" and the dates need to be populate till the "$lastCell".Can someone let me know how this can be done. Thank you.

A
existingArray.txt
arrrayToInclude.txt
0
aej1973
Asked:
aej1973
1 Solution
 
Scott MadeiraCommented:
First of all, if $nudates is supposed to be an array then you need to do something like this to save it as an array:

// Initialize the variable
$nudates = null;

for ($count=1; $count<60; count++}
{
    // Calculate the date and save it to the array
    $date = strtotime("+$count day", $timestamp);
    $nudates[] = date("M d", $date);
}

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In your code you will need use a counter for your array and then insert the next value each time through the inner loop.  you will need to make sure you don't try to put more than 59 dates in your table because you are only making 59 date values.


// set counter for your date array
$i = 0;
for($l=1; $l<$lines; $l++){
    $output.= "<tr>\n";
    // iterate through each column
	
    for($c=1; $c<$cols; $c++){
    	// determine this cell number
    	$cellnumber = $l*10+$c;		
    	// determine this cell color
    	if($cellnumber >= $firstCell && $cellnumber <= $lastCell)
		{
    		$color = "#99CC66";    // defined range's cell color
    	}
		else
		{
    		$color  = "white";  // default cell color
    	}
		
		    $output.= "<td style=\"background-color:$color;\" name=\"$cellnumber\">$nudates[$i]</td>\n";
                     $i++;
    }
    $output.= "</tr>\n";
}

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aej1973Author Commented:
Thanks a ton. Exactly what I was looking for.
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