Conditional formatting in Access: Adding symbol to field

Posted on 2012-04-03
Medium Priority
Last Modified: 2012-08-13

I have an access form with, for the purpose of this question, has two fields:

"Action" and "Action Type"

"Action" is a text field. It is just the name of any action.

"Action Type" is a number field. It defines an action as being a task or a meeting. 1 for task, 2 for meeting.

When the "Action Type" is 2, I want whatever is in the "Action" field preceded by a *.

Example: Worked on this database till my eyes popped out. (Action Type 1)
                *Meeting about how I cry too much when working on databases (Action Type 2)

How should I do this? And ideas?

Thank you!
Question by:Megin
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LVL 61

Expert Comment

ID: 37804133
I would suggest not storing the * with your data.

Instead, create a label next to the Action field that just displays a "*"

then in the Current Event of your form:

Me.lblAsterisk.Visible = (Me.[Action Type] = 2)

Author Comment

ID: 37814608
I am afraid this isn't working for me. For some reason, either all of the tasks have an asterisk or none of them do.

Any more ideas?

Accepted Solution

Megin earned 0 total points
ID: 37816640
I solved this by adding a special query field:
                           strAction: Iif([actType]=2,"*" & [ActName],[ActName])

Thank you to those who took the time to try and help! This site is fantastic!
LVL 61

Expert Comment

ID: 37816989
Sorry I missed your follow up question.

The reason you were seeing "all or none" with the solution I posted is most likely because you are using continuous forms (all unbound controls "look" the same).  That solution would have worked out okay with a form in single form view.

It's always a good idea to include a note in your original post to make it clear when you are using continuous forms or datasheets.  The solutions are generally straight forward  -- but different depending on the form view.

Glad you've got it resolved, and thanks for posting the solution.

Author Closing Comment

ID: 37831679
I found the solution on another website and wanted to close out this question. Someone on UtterAccess gave me the answer I needed.

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