# Display 3 months ago time span taking into account not all months are 31 days... how?

I'm trying to determine how to display the following:
2012-01-01 (which is 3 months ago on the first of the month excluding the current month we're in)
My code below (which I'm certainly not married to if there is a better way), does the above
Problem is I also need to show the last day of the month, 3 months ago, taking into account not all months have 31 days??

How do you accomplish that?

``````\$monthdate = date("Y-m");
\$threemonth = strtotime ( '-3 month' , strtotime ( \$monthdate ) ) ;
\$threemonth = date ( 'Y-m' , \$threemonth );
echo \$threemonth."-01";
``````
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Commented:
Try the following:

``````\$threemonthsago = mktime(0,0,0,date("m")-3,1,date("Y"));
echo date("Y/m/d", \$threemonthsago);
``````

Josh

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Author Commented:
Hi,
thats great, shows me 3 months ago on the 1st of the month, cleaner then my method for sure.
How can I get it to show the last day of the month regardless of how many days are in the month?
Author Commented:
That was all I actually needed to complete afterall.
thanks.
Commented:
I'm not 100% if this will work correctly.

This should display 2012/1/31. Current month -2 and then back one day...

``````\$threemonthsago = mktime(0,0,0,date("m")-2,-1,date("Y"));
echo date("Y/m/d", \$threemonthsago);
``````
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