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File access error using asp.net upload control

Posted on 2012-04-04
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Last Modified: 2012-04-09
I have an asp.net website that gets an access denied error when executing the below code.
The website is using an application pool configured with a service account.

 MemoryStream destination = new MemoryStream();
                    using (FileStream fileStream = File.OpenRead(this.FileUpload1.PostedFile.FileName))
                    {
                        memStream = new MemoryStream();
                        memStream.SetLength(fileStream.Length);
                        fileStream.Read(memStream.GetBuffer(), 0, (int)fileStream.Length);
                    }

Previously, I used the below code successfully to read the file.
////Load FileUpload's InputStream into Byte array
                    //byte[] imageBytes = new byte[FileUpload1.PostedFile.InputStream.Length + 1];
                    //FileUpload1.PostedFile.InputStream.Read(imageBytes, 0, imageBytes.Length);

I want to create a memory stream to process the text file.  Any tips is greatly appreciated.
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Comment
Question by:edbrinkm
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5 Comments
 
LVL 7

Expert Comment

by:Lalit Chandra
ID: 37807073
you can do the your task in the following way

            Stream sw     = FileUpload1.PostedFile.InputStream;
            byte[] buffer = new byte[sw.Length];  
            sw.Read(buffer, 0, buffer.Length);  
            sw.Close();  


Refer : http://forums.asp.net/t/1604848.aspx/1

Hope you will fix up your issue.
0
 

Accepted Solution

by:
edbrinkm earned 0 total points
ID: 37807113
A coworker gave me a solution.

    Stream theStream;
    theStream = FileUpload1.PostedFile.InputStream;
        using (Microsoft.VisualBasic.FileIO.TextFieldParser MyReader = new Microsoft.VisualBasic.FileIO.TextFieldParser(theStream))
        {
//process file

}
0
 
LVL 7

Expert Comment

by:Lalit Chandra
ID: 37807224
I have given the code (help) first, thenafter how can you simply close the post like this as my comment was right.
0
 

Author Comment

by:edbrinkm
ID: 37807238
I had attempted that code before.  The problem is that it converts the text to a byte array.  I need it as a text file/string format.
0
 

Author Closing Comment

by:edbrinkm
ID: 37822731
it works.  no errors
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