oracle date query

Need a parameter for No of weeks of schedule.

define d_first_day_week  date
= date(7- mod(days(sysdate) , 7)) + (days(sysdate)) - 7)

define d_weeks  date =
date(days(d_first_day_week) + nconvert(getsys(parameter_name)) * 7)

Need help inh translating this to oracle
so that I can use in the query

select  a.department_id,a.payroll_id,
        a.schedule_date,a.start_time,a.start_ampm,
        a.end_time,a.end_ampm,a.total_hours,
        a.short_description,s.site_name,s.city_name
from off_duty a, sites s,blood_drives bd
where a.site_code = s.site_code(+)
and a.site_code = bd.site_code(+)
and a.schedule_date = bd.drive_date(+)      
and a.department_id = 5
and a.schedule_date = parameter_name(no of weeks of schedule)
LVL 6
anumosesAsked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

sdstuberCommented:
you have declarations that use non-Oracle functions  - what do those functions do?

you have a query that uses another non-Oracle function - what does that function do?


there is no input, nor expected output
what is the question?
anumosesAuthor Commented:
The logic is I have to use 1 to 5 weeks.
The first day has to be a sunday. so 1 - sunday to saturday. (april 8th to april 14th  2012)
2 weeks -( april 8th to april 21st 2012).
So when the user puts 1 then I have to to take the schedule_date = to that parameter. Internally convert 1 to sunday to saturday
anumosesAuthor Commented:
No I take back. I will post very soon what is required
Determine the Perfect Price for Your IT Services

Do you wonder if your IT business is truly profitable or if you should raise your prices? Learn how to calculate your overhead burden with our free interactive tool and use it to determine the right price for your IT services. Download your free eBook now!

sdstuberCommented:
>>> convert 1 to sunday

I understand that part,    

DECODE(n,
              1, 'Sunday',
              2, 'Monday',
              3, 'Tuesday',
              4, 'Wednesday',
              5, 'Thursday',
              6, 'Friday',
              7, 'Saturday'
             )



the rest I still don't know what you want to do.  Please provide sample data and expected output.
sdstuberCommented:
sorry, didn't see the second post
anumosesAuthor Commented:
OK. here it is. If I am running the report today, then today is 4th april 2012. So I have to go back to sunday ie is the 1st april. Then from that sunday add no of weeks schedule, (1-5)
slightwv (䄆 Netminder) Commented:
Beginning of the week is:  trunc(sysdate, 'DAY')

>>add no of weeks schedule, (1-5)

Are you then wanting to addd 'weeks' to that?  if so, sumple math.
sdstuberCommented:
this will give you Sunday of the current week

trunc(sysdate,'d')


this will give you Sunday of the current week plus one week

trunc(sysdate,'d') + 7

this will give you Sunday of the current week plus two weeks

trunc(sysdate,'d') + 14

this will give you Sunday of the current week plus five weeks

trunc(sysdate,'d') + 35


if you have number of weeks as a number parameter "n",  try this...

trunc(sysdate,'d') + (7 * n)

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
anumosesAuthor Commented:
select trunc(sysdate, 'DAY') from dual

TRUNC(SYSDATE,'DAY')
4/1/2012

So its sunday. Then I have to add 1(1 week) 2 (2 weeks) to 4/1/2012 and that has to be used in the query

select  a.department_id,a.payroll_id,
        a.schedule_date,a.start_time,a.start_ampm,
        a.end_time,a.end_ampm,a.total_hours,
        a.short_description,s.site_name,s.city_name
from off_duty a, sites s,blood_drives bd
where a.site_code = s.site_code(+)
and a.site_code = bd.site_code(+)
and a.schedule_date = bd.drive_date(+)      
and a.department_id = 5
and a.schedule_date = ????????
anumosesAuthor Commented:
OK got you. Will try
anumosesAuthor Commented:
select trunc(sysdate,'d'), trunc(sysdate,'d') + (7 * 1) from dual

TRUNC(SYSDATE,'D')      TRUNC(SYSDATE,'D')+(7*1)
4/1/2012                             4/8/2012

4/1/2012 is correct. But I have to get 4/7/2012 ( saturday)
anumosesAuthor Commented:
select trunc(sysdate,'d'), trunc(sysdate,'d') + (6 * 1) from dual

This is what I did.
slightwv (䄆 Netminder) Commented:
>>This is what I did.

Does that get you what you want?

If so, don't forget to close out the question.

If not, what else do you need?
sdstuberCommented:
I suggest doing this...

select trunc(sysdate,'d'), trunc(sysdate,'d') + -1 + (7 * 1) from dual

if you try multiplying 6 for multiples of weeks you'll get the wrong result.
anumosesAuthor Commented:
thanks
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Oracle Database

From novice to tech pro — start learning today.