# pad 8 digit binary number representations - in C#

string binValue = Convert.ToString(64, 2);

But I need to show all 8 digits.

So

string binValue = Convert.ToString(6, 2);

which would normally be "110" would need to be shown as:

00000110

How?

Thanks!!!  :)
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Commented:
``````           var binStr = Convert.ToString(2, 2);

var sb = new StringBuilder();
for(int i=0;i<8-binStr.Length;i++)
{
sb.Append("0");
}

sb.Append(binStr);
``````

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Web developerAuthor Commented:
... is what I ended up doing as well.

Thanks,

Tom

Q:  .NET does not provide a cleaner way to do this?

Something like, "I am representing this value as an 8-bit binary.  I want each digit to be represented, even if it is OFF (1 would be "00000001", 64 would be "10000000")"

Without having to "brute force" pad the difference with "0"?
Commented:
well this is default behaviour, any leading zeros are ripped off....
Web developerAuthor Commented:
ok

:)
PresidentCommented:
string binValue = Convert.ToString ( 6, 2 ).PadLeft ( 8,'0' );
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