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delete duplicates of 3 column combination

select COUNT(*),COL1,COL2,COL3 from tblOCDELStudent_1011 group by COL1,COL2,COL3 having COUNT(*) >1

gives records that have the combination of COL1,COL2,COL3 more than once..

how can we eliminate duplicates that all of them will have exactly one count only.. that is, the above query should give no results at all, and so we can delete ..

if the count is 3 it should have 2 deletes.. and if 4, then 3 and so forth..
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awking00
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Can you provide a description of the tblOCDELStudent_1011 table?
Is there an identity column or other unique value on each row?

If not, you might have to use a cursor with TOP.
Try

delete t
from tblOCDELStudent_1011 t
where  pk = (select top 1 pk, COUNT(*),COL1,COL2,COL3 from tblOCDELStudent_1011 group by COL1,COL2,COL3 having COUNT(*) >1);
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Scott Pletcher
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If you have a primary key PK_ID then it could be something like this
--delete tblOCDELStudent_1011 
select *  -- first test it as select, then change it to delete
from  tblOCDELStudent_1011  as t1
inner join (
select COL1,COL2,COL3,min(PK_ID)  as MIN_PK_ID
from tblOCDELStudent_1011 
group by COL1,COL2,COL3 having COUNT(*) >1
) as t2 on t1.col1 = t2.col1
 t1.col2 = t2.col2
 t1.col3 = t2.col3
 t1.PK_ID <> t2.MIN_PK_ID

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25112

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let me try your solutions..

the pk is the 3 columns ... col1/col2/col3 combination.. (of course, PK is not enforced yet.. that is the goal of this project )
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the table structure is

COL1 varchar      12
COL2 datetime      
COL3 varchar      4
COL4 numeric      9
COL5 char      1
COL6 varchar      4
COL7 varchar      4
COL8 varchar      4
COL9 char      1
COL10 varchar      30
COL11 char      1
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awking00, your syntax gives this issue..
Windowed functions do not support integer indices as ORDER BY clause expressions.


scott, i am getting stuck in declaring your variables right.. i am working on it..

ashok- your last query - is that with PK or without..?
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I think it will return the expected result ,,,,, you can analysis data by this.

select col1, col2, col3 from (
select row_number() over( partition by col1 order by col1
) as row,col1, col2, col3
from table_A) a --where row >1

and after that  if you are satisfied then....

delete from (
select row_number() over( partition by col1 order by col1
) as row,col1, col2, col3
from table_A) a where row >1
Deepak,

select col1, col2, col3 from (
select row_number() over( partition by col1 order by col1
) as row, col1, col2, col3
from table_A) a where row > 1;

and after that  if you are satisfied then....

delete a from (
select row_number() over( partition by col1 order by col1
) as row, col1, col2, col3
from table_A) a where row > 1;

You are missing "a" near the delete as shown above.

HTH
Ashok
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Did you try my method with the change in the order by clause?
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ashok/awking00

your syntax worked.. many thanks.. i tweaked scott's also to work.. (I did it in transaction and rolled back to test)
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ASKER

thanks for the idea Deepak
Deepak,

delete from (
select row_number() over( partition by col1 order by col1
) as row,col1, col2, col3
from table_A) a where row >1;

Above does NOT work.
Do not say "I think....".

I tested it in SQL 2008 Management Studio.
After adding "b", it worked.

If you test it, you will know.

Thanks,
Ashok
By the way if you also add "a" to select like this....

select a.Menu_Date from
(
select row_number() over(partition by Menu_Date order by Menu_Date
) as row, Menu_Date
from DailyLunch) a where row > 1;

It works.

Ashok
Ashok

you r right

it is working with 'a'

i apologize
sorry for being mistake
Deepak,

It's ok.  We all make mistakes.
Sometimes it is better to test before making any judgements.

Thanks,
Ashok