Using one statement or transaction to insert from one query into 4 tables

Hey experts

The problem I’m trying to solve is that I wrote a query and would like
to Insert the results of this query into 4 tables

select
COLUMN1 as VARIABLE1, 
COLUMN2+'-'+COLUMN3+'-'+COLUMN4 as VARIABLE2,
LEFT(COLUMN2, 2) as VARIABLE3,
RIGHT (COLUMN2, 4) as VARIABLE4,
COLUMN2 as VARIABLE5,
COLUMN3 as VARIABLE6,

case   when COLUMN2 like '%1%' then 'CASE1' 
	 when COLUMN2 like '%2%' then 'CASE2'
	 when COLUMN2 like '%3%' then 'CASE3'
	 end as VARIABLE7,

from TABLE1.COLUMN1 where TABLE1.COLUMN2 like 'MATCH' 
and TABLE2.COLUMN3 = TABLE2.COLUMN4

Open in new window


Prior to inserting I’d like To Check if the data exists in the target tables

Check if exists if not then insert rows for Variables 1,2,3,7 into table 5
Check if exists if not then insert rows for Variables 1,2 into table 6
Check if exists if not then insert rows for Variables 2,7,4 into table 7
Check if exists if not then insert rows for Variables 3,7 into table 8

And finally generate a report of the data inserted.

I learned that the if not exists insert can only run on one table whereas I’m trying to obtain a solution capable of running an insert on multiple tables, so I’m guessing a transaction would be needed? I was able to find a similar thread in SO, but I don’t know how to make it work...
http://stackoverflow.com/questions/175066/sql-server-is-it-possible-to-insert-into-two-tables-at-the-same-time
 
$qry = "INSERT INTO table (one, two, three) VALUES('$one','$two','$three')";
$result = @mysql_query($qry);

$qry2 = "INSERT INTO table2 (two) VALUES('$two')";
$result = @mysql_query($qry2);

Open in new window

Daniel993Asked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Qlemo"Batchelor", Developer and EE Topic AdvisorCommented:
Not clear what you are after.
First, you need to define what makes a row we can search for in each of the target tables, i.e. the "keys" for each table.
Then you can only insert into a single table per statement - if it is a requirement that the  rows do not exist in ANY table, you need to check that first, and then execute inserts.
If you, however, just want to make sure not to create duplicate rows, and just need to check that table by table, the INSERT ... SELECT ... if not exists (select ...) is the correct approach.
0
Daniel993Author Commented:
Hey, thanks for a quick reply...

Indeed I'd like to avoid creating duplicate rows table by table (hence the INSERT...Select approach), as for the keys, in tables 5 and 6 the key is variable 1 and in tables 7 and 8 the key is variable 7
0
Qlemo"Batchelor", Developer and EE Topic AdvisorCommented:
One way is to use a temporary table to hold the values, another to keep values in local variables.
select
COLUMN1 as VARIABLE1, 
COLUMN2+'-'+COLUMN3+'-'+COLUMN4 as VARIABLE2,
LEFT(COLUMN2, 2) as VARIABLE3,
RIGHT (COLUMN2, 4) as VARIABLE4,
COLUMN2 as VARIABLE5,
COLUMN3 as VARIABLE6,

case   when COLUMN2 like '%1%' then 'CASE1' 
	 when COLUMN2 like '%2%' then 'CASE2'
	 when COLUMN2 like '%3%' then 'CASE3'
	 end as VARIABLE7

into #vals
from TABLE1.COLUMN1 where TABLE1.COLUMN2 like 'MATCH' 
and TABLE2.COLUMN3 = TABLE2.COLUMN4

insert into table5 (col1, col2, col3, col4)
select variable1, variable2, variable3, variable7 from #vals
where not exists (select * from table5 where col1 = #vals.variable1)

insert into table6 (col1, col2)
select variable1, variable2 from #vals
where not exists (select * from table6 where col1 = #vals.variable1)

insert into table7 (col1, col2, col3)
select variable2, variable7, variable4 from #vals
where not exists (select * from table7 where col2 = #vals.variable7)

insert into table8 (col1, col2)
select variable3, variable7 from #vals
where not exists (select * from table8 where col2 = #vals.variable7)

Open in new window

0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
Daniel993Author Commented:
Thanks, it works brilliantly
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Microsoft SQL Server 2005

From novice to tech pro — start learning today.