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java List question

Posted on 2012-04-07
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Last Modified: 2012-04-12
Hello there,

can somebody please explain this line of code.thanks

List<NameValuePair> params = new ArrayList<NameValuePair>();

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cheers
Zolf
0
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Question by:zolf
7 Comments
 

Author Comment

by:zolf
ID: 37820659
what i am trying to do is

I have these two methods. i am using the executeHttpPost method in the login method to pass 2 parameter.but i get error in the login method when i try to add the String to the List.please help

public String executeHttpPost(List<NameValuePair> data)
	{
		try
		{
			HttpClient client = getHttpClient();
			//String postURL = furl;
			/*Log.d("ZAJ sendPost URL", postURL + " " + data.get(0).toString() + " "
					+ data.get(1).toString());*/
			HttpPost post = new HttpPost(url);
			List<NameValuePair> params = new ArrayList<NameValuePair>();
			params.add(new BasicNameValuePair("username", data.get(0).toString()));
			params.add(new BasicNameValuePair("password", data.get(1).toString()));
			UrlEncodedFormEntity ent = new UrlEncodedFormEntity(params, HTTP.UTF_8);
			post.setEntity(ent);
			HttpResponse responsePOST = client.execute(post);
			HttpEntity resEntity = responsePOST.getEntity();
			if (resEntity != null)
			{
				String response = EntityUtils.toString(resEntity);
				Log.i("RESPONSE", response);
				return response;
			}

		}
		catch (Exception e)
		{
			e.printStackTrace();
		}
		return null;
	}

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==============================================

public boolean login(String username,String password)
	{
		/*
		 * Log.d("ZAJ URL", url + "?action=login&username=" +
		 * data.get(0).toString() + "&password=" + data.get(1).toString());
		 */

		//String fullURL = url + "?action=login";
		
		List<NameValuePair> data = new ArrayList<NameValuePair>();
		
		data.add(username);
		data.add(password);
		
		
		String response = executeHttpPost(data);

		String delimiter = "\\|";

		String[] temp = response.split(delimiter);

		if (temp[0].equals("100"))
		{
			return true;
		}
		else
		{
			return false;
		}
	}

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0
 
LVL 23

Accepted Solution

by:
basicinstinct earned 200 total points
ID: 37820780
Your list only accepts an instance of "NameValuePair". Is a string an instance of NameValuePair? No. So you can't put a string in it.
0
 
LVL 25

Expert Comment

by:Tomas Helgi Johannsson
ID: 37821119
Hi!

What error do you get ?

Regards,
    Tomas Helgi
0
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LVL 2

Assisted Solution

by:Elbassel
Elbassel earned 100 total points
ID: 37821216
This line means that:
The list stores objects of type NameValuePair class, so you can't add any other objects of another type.

Best wishes
0
 
LVL 26

Assisted Solution

by:ksivananth
ksivananth earned 100 total points
ID: 37822458
try this,

data.add(new BasicNameValuePair("username", username));
data.add(new BasicNameValuePair("password", password));
0
 
LVL 20

Assisted Solution

by:Sathish David Kumar N
Sathish David  Kumar N earned 100 total points
ID: 37836144
if your using apache http client then you can use name NameValuePair. thats is using messaging purpose .

 ksivananth mentioned correct solution for that
0
 

Author Closing Comment

by:zolf
ID: 37841084
thanks
0

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