Update a dynamic text box in excel chart automatically


I have a  chart in excel 2007 that a user updates almost daily. The chart gets updated appropriately using a named range that contains the offset function (=OFFSET('T'!$U$17,15,0,1,COUNTA('T'!$U$17:$EA$17)).  I would like to improve this chart by adding a text box that updates with the last value in row that is based on a calculation. I can link the text just fine, but the next day when new data is entered, the text box does not get automatically updated.


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I don't think you need VBA for this.  Does that text box you create have a formula referencing a cell in it, and if you update that cell, the textbox gets updated?

Is it that you need a formula for the last value in a column?  Are these values text or numeric?

The following will return the last value in a given column, say, for column A:


See attached demonstration with chart/text-box


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DiaphanosomaAuthor Commented:
I'm going to modify to work on my data, but I don't understand the formula at all! I ran it through the formula evaluator and that didn't help either.
Why are you looking for a  value of 2?
Why is there division in the lookup vector?
Better yet can you explain how and why the formula works?


I'm happy to do so.  There are actually several different formulas you could use.

E.g., find the last number in a column:


find the last text in a column


find the last value (number or text) could be a complicated version of the above, or we can use LOOKUP.  Let me explain LOOKUP by talking about the match and lookup (including vlookup) functions in general:

1.  They all THINK your data is sorted - this is important
2.  MATCH/VLOOKUP have options for exact match, or NEXT HIGHEST value (re: the largest value being looked for that is less than or equal to what you're looking for).
3.  The Lookup function also find either the match or next highest value.

So, in the case of Lookup(2,1/(A:A<>""),A:A) what is going on?

The first parameter is the search parameter,
The second parameter is what is being searched.

These two parameters act together to create an index which goes against the last parameter.  Kind of how INDEX/MATCH works but all in one formula.

Let's talk about the 1/(A:A<>"").  This returns an array of 1/(TRUE's and FALSEs) which returns an array of 1's and #DIV!0's.  Note the maximum valid value of 1/(A:A<>"") is 1.  You can combine this with other arrays to make multiple criteria work.

So, if we do a Lookup(2,1/(A:A<>""),A:A) we would get the LAST instance of a value that is non blank in column A.  Why?  Well, Lookup thinks the data is sorted, so it starts at the bottom of the range and works its way up, looking for the maximum value (because we're using 2 and 1 is the only valid value) until it finds it.  As soon as it finds a valid value that is less than or equal to 2, it uses that.  That's why it returns the last value.

Hope this helps.

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PS - if you know your data is numeric, you can use INDEX/MATCH as above, or the Lookup:

=LOOKUP(99^99,A:A,A:A)  99^99 a very big number, so would find the next highest - thinking its sorted, would return the next valid number

and if you know your data is text,  you can use:

=LOOKUP(REPT("z",20),A:A,A:A)  rept("z",20) a very big text value, so would find the next highest - thinking its sorted, would return the next valid text value

Why did I use =Lookup(2,1/(A:A<>""),A:A)  ???

As I didn't know if it was text or numeric, I just gave you a lookup that used criteria A:A<>"" so I KNEW the result would be a correct one.

Rory ArchibaldCommented:
>>"Well, Lookup thinks the data is sorted, so it starts at the bottom of the range and works its way up"

It's a binary search, I think you'll find, which is why it's much faster than exact matches.
DiaphanosomaAuthor Commented:
Perfect solution and explaination.

Thanks so much.

>>It's a binary search, I think you'll find, which is why it's much faster than exact matches.

That's good to know, but the reason it finds the last cell (meeting the criteria of a very large number/text stream that doesn't exist in the data) is due to the fact it assumes the data is sorted
Rory ArchibaldCommented:
Correct - I wasn't disputing that part (otherwise a binary search wouldn't work for LOOKUP). :)
Got it!

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