Find the first number in a string

If the string is "RE: 1 xxxxx" then what is the code that will returne the value 1? Thanks!
Sasha42Asked:
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DatabaseMX (Joe Anderson - Microsoft Access MVP)Database ArchitectCommented:
You can use Val(YourString)

mx
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DatabaseMX (Joe Anderson - Microsoft Access MVP)Database ArchitectCommented:
Now, when you say First Number ... val() will return N number of digits at the start of a string ... except ... if the first digit is zero AND there are more digits after that, the zero will get dropped.

Is the number always the first character in your string ?

If so .... the just Left(YourString, 1)


mx
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Lee W, MVPTechnology and Business Process AdvisorCommented:
varString = "Re: 1 xxx"

For x = 1 to Len(varString)
   if IsNumeric(Mid(varString, 1, 1)) = True Then FirstNumber =  Mid(varString, 1, 1)
   exit for
Next

Open in new window

If you're looking for more than a single digit number or potentially more, then we need to do a little more work.
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Sasha42Author Commented:
Dim varstring As String
Dim firstnumber As Integer

varstring = "re: 3 xxxxx"
For x = 1 To Len(varstring)
   If IsNumeric(Mid(varstring, 1, i)) = True Then firstnumber = Mid(varstring, 1, i)
 
   Exit For
Next
  MsgBox (firstnumber)

The above returns a 0
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Sasha42Author Commented:
Dim varstring As String
Dim firstnumber As Integer

varstring = "re: 3 xxxxx"
For x = 1 To Len(varstring)
   If IsNumeric(Mid(varstring, 1, 1)) = True Then firstnumber = Mid(varstring, 1,1)
 
   Exit For
Next
  MsgBox (firstnumber)

Correction: The above returns a 0
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tliottaCommented:
Do you want "first number" or "first digit"?

The above returns a 0

In both comments, you're using "For x =...", but you never use 'x' anywhere within the loop. In the first comment, you use 'Mid(varstring, 1, i)'. Try using 'Mid(varstring, x, 1))' instead.

Tom
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Sasha42Author Commented:
I want the first number.  This still returns a zero.  Thanks for your help!

Dim varstring As String
Dim firstnumber As Integer

varstring = "re: 3 xxxxx"
For x = 1 To Len(varstring)
   If IsNumeric(Mid(varstring, x, 1)) = True Then firstnumber = Mid(varstring, x, 1)
 
   Exit For
Next
MsgBox (firstnumber)
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Sasha42Author Commented:
I tried this too:

If IsNumeric(Mid(varstring, 1, x)) = True Then firstnumber = Mid(varstring, 1, x)
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DatabaseMX (Joe Anderson - Microsoft Access MVP)Database ArchitectCommented:
Can you give some additional examples of the strings ?
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Sasha42Author Commented:
I am pulling data out of the subject line of an Outlook message:

FW: 1 xxxxxxx - Approved
RE:  3 xxxxxxx - Denied
1 xxxxxxx - Approved

I want to pull the first number, 1,3,1

Thanks!
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DatabaseMX (Joe Anderson - Microsoft Access MVP)Database ArchitectCommented:
Try this function ... works for all the cases you listed:


Public Function mGetFirstNumber(sStr As Variant) As Variant

''
''  FW: 1 xxxxxxx - Approved
''  RE:  3 xxxxxxx - Denied
''  1 xxxxxxx -Approved
''  abcdefghi9
    If IsNull(sStr) Then Exit Function
   
    If IsNumeric(Left(sStr, 1)) Then
        mGetFirstNumber = Left(sStr, 1)
        Exit Function
    End If
   
    Dim iCnt As Long
    For iCnt = 1 To Len(sStr)
        If IsNumeric(Mid(sStr, iCnt, 1)) Then
            mGetFirstNumber = Mid(sStr, iCnt, 1)
            Exit Function
        End If
    Next iCnt

End Function
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Sasha42Author Commented:
Perfect! Thanks!
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