Solved

java mouseListener movement bug

Posted on 2012-04-11
2
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Last Modified: 2012-04-17
Hi,

I created an application where you can set several rectangles with Strings in on a panel.
Each of these rectangles can be moved by click-dragging.

Code:
public void mousePressed(MouseEvent e) {
		preX = this.getPosition().x - e.getX();
	    preY = this.getPosition().y - e.getY();
	    
	    if (getBounds().contains(e.getX(), e.getY())){
		    this.pressed = true;
	    }
	}

	public void mouseReleased(MouseEvent e) {
		this.pressed = false;
	}

	public void mouseDragged(MouseEvent e) {
		if(this.pressed){
			System.out.println(e.getX() + " - " + e.getY());
			setPosition(new Point(e.getPoint().x + preX, e.getPoint().y + preY));
		}
	}

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Now I found a bug which after some thinking seems logic but I can't seem to figure out a simple solution for it to fix.

Bug is the following:
When two rectangles are intersecting and you click (on the intersection) you move both of the rectangles instead of 1.

This is logic, but what could I do to fix this?
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Question by:Mutsop
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2 Comments
 
LVL 16

Accepted Solution

by:
imladris earned 500 total points
ID: 37833231
Simplest solution I can think of is to maintain a list of rectangle objects. Then, when you find that a rectangle contains the mouse event call a method to set pressed. This method should have access to the list of the rectangles. The method should ensure that only *one* rectangle ever has the pressed flag set to true.

So, whenever it is called to set it to true, it should first reset the pressed flag for all rectangles. This will ensure that there is only ever one rectangle that will be moved.
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LVL 3

Author Closing Comment

by:Mutsop
ID: 37855560
Thanks
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