grep with regular expression

mysql -S /tmp/mysql.sock -e ' SHOW GLOBAL STATUS  ' | grep 'Com_insert'
 which gives bellow result

Com_insert      353
Com_insert_select       0

but this

/opt/mysql/server-5.5/bin/mysql -S /tmp/mysql.sock -e ' SHOW GLOBAL STATUS  ' |  grep 'Com_insert' | grep -v 'Com_insert_select'

it gives
Com_insert      353
which is right..
but is there any clean way to write this command  so that
i only get 'Com_insert      353'

i meant : by using regular expression or regular expresson + awk   ??
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A pure regular expression equivalent to  grep 'Com_insert' | grep -v 'Com_insert_select'  can get a little awkward to write.
It may be easier to use something like
perl -ne 'print if /Com_insert(?!_select)/'

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Maciej SsysadminCommented:
use -w option for grep:

/opt/mysql/server-5.5/bin/mysql -S /tmp/mysql.sock -e ' SHOW GLOBAL STATUS  ' |  grep -w 'Com_insert'
As a single egrep expression, it would be
egrep 'Com_insert($|[^_]|_($|[^s])|_s($|[^e])|_se($|[^l])|_sel($|[^e])|_sele($|[^c])|_selec($|[^t]))'
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grep -w 'Com_insert'
is not equivalent to grep 'Com_insert' | grep -v 'Com_insert_select'
because grep 'Com_insert' | grep -v 'Com_insert_select' would match something like "Com_insertion"
whereas grep -w 'Com_insert' would not
Maciej SsysadminCommented:
I agree - it's not equivalent, but it's an answer for fosiul's question (with his output).
for the specific output listed in the question,
grep 'Com_insert' | awk 'NR==1'
would also be an answer,
so would
grep 'Com_insert     353'
Maciej SsysadminCommented:
I won't argue with this - your perl solution is the most general one - I agree.
But - for this specific question, where input for grep is "show global status" output - my version is simpler, and will not cause unwanted output. And yes - author can also run "grep 'Com_insert '" (with space at the end). IMO -w option is better than adding space. It's (still IMO) also better then your perl - it's simpler and shorter. If author wants to use it in future in some other cases, than your perl may be better (it depends on input for grep/perl).

One more solution - without any grep, awk, perl, etc:

/opt/mysql/server-5.5/bin/mysql -S /tmp/mysql.sock -e ' SHOW GLOBAL STATUS  where variable_name="Com_insert"'
Maciej SsysadminCommented:
Above will output headers also. The one with desired output only (with -B -N options for mysql):

/opt/mysql/server-5.5/bin/mysql -S /tmp/mysql.sock -e ' SHOW GLOBAL STATUS  where variable_name="Com_insert"' -BN
fosiul01Author Commented:
Hi thanks for variataion ...

just one more variation i want to add , this also gives the accurate result ..

/opt/mysql/server-5.5/bin/mysql -S /tmp/mysql.sock -e ' SHOW GLOBAL STATUS  ' | awk '$1~/^Com_insert$/ {print $2}'
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