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decode or case statement in oracle query

I have a view

create or replace view off_duty (site_code,
                                 site_code1,
                                 department_id,                                                 department_name,
                                 schedule_date,                                                 start_time,                                                 start_ampm,
                                 end_time,                                                 end_ampm,                                                 total_hours,
                                 short_description,                                                 reason_code,                                                 payroll_id,                                                 emp_name,                                                 mail_last_name,                                                 ss_mob)
             as
select d.site_code,ds.site_code,eu.department_id,d.department_name,
       ds.schedule_date,ds.start_time,ds.start_ampm,
       ds.end_time,ds.end_ampm,ds.total_hours,
       nar.short_description,nar.reason_code,
         ds.payroll_id,FIRST_NAME||' '||MAIL_LAST_NAME,
         mail_last_name,d.ss_mob
  from emp_unexcld eu,
       department d,
       dept_staff ds,
       not_avail_reason nar
where eu.payroll_id = ds.payroll_id
  and ds.department_id = d.department_id(+)
  and ds.reason_code = nar.reason_code  
  and nar.schedule_required_flag = 'Y'
-----------------------------------
If department_id in (5,95) then I have to get ds.site_code else d.site_code
0
anumoses
Asked:
anumoses
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2 Solutions
 
slightwv (䄆 Netminder) Commented:
case when department_id in (5,95) then ds.site_code else d.site_code end
0
 
anumosesAuthor Commented:
sorry

select site_code,site_code1 from
off_duty
where payroll_id = 'ZZW0024100'
AND SCHEDULE_DATE between '09-apr-2012' and '12-apr-2012'

----------------

SITE_CODE|SITE_CODE1
AU01|MC31
AU01|CS28
EL01|
EL01|

If Site_code1 is not null then take site_code1 elseif site_code1 is null then get site_code
0
 
anumosesAuthor Commented:
select schedule_date,site_code,site_code1 from
off_duty
where payroll_id = 'ZZW0024100'
AND SCHEDULE_DATE between '09-apr-2012' and '12-apr-2012'

------------------

SCHEDULE_DATE|SITE_CODE|SITE_CODE1
4/12/2012|AU01|MC31
4/11/2012|AU01|CS28
4/10/2012|EL01|
4/9/2012|EL01|
0
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anumosesAuthor Commented:
select a.emp_name,
       to_char(schedule_date,'fmDy')WEED_DAY,
       schedule_date,
         replace(to_char(a.start_time/100, 'fm00.00'), '.', ':')||a.start_ampm start_time,
         replace(to_char(a.end_time/100, 'fm00.00'), '.', ':')||a.end_ampm end_time,
         to_char(a.total_hours/100, 'fm00.00') total_hours,
       a.short_description,
         a.department_name,
         s.city_name,a.ss_mob
  from off_duty a, blood_drives bd,sites s,dept_sched des
 where a.site_code = s.site_code(+)
   and a.schedule_date = bd.drive_date(+)
   and a.site_code = bd.site_code(+)
   and des.department_id = a.department_id
   and a.schedule_date between trunc(sysdate,'d') and last_sched_date
-------------------

This is my final report query. So may be we want to add the site code here, with the logic that I need.
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slightwv (䄆 Netminder) Commented:
>>If Site_code1 is not null then take site_code1 elseif site_code1 is null then get site_code

This is a completely different requirement than the question asked.

If you asked the wrong question, I suggest you close this one and ask the correct one.

Anyway, once you understand the CASE statement logic, writing the statement is pretty straight forward.

Can you not use the similar is null login from your other question to figure out this one?

http://www.experts-exchange.com/Database/Oracle/Q_27668956.html
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QlemoC++ DeveloperCommented:
Use   @NVL(site_code1, site_code)
0
 
anumosesAuthor Commented:
thanks
0

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