Solved

Update a chart control as variables change

Posted on 2012-04-11
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Last Modified: 2012-04-12
Hi All

One of the forms in my project has a basic line graph created using the chart control. It shows market size in units over 12 periods. The 12  Y-axis values are read from 12 text boxes that start with default values read from a file. The form's load event then has code that reads these into an array and creates a series to display on the graph. So far so good, the graph does display correctly.

What I want, however, is for the user to be able to enter new figures into the text boxes and for the graph to update automatically as the array variables are changed.

Any suggestions?

Regards

Terry
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Question by:Terrygordon
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4 Comments
 
LVL 17

Expert Comment

by:nepaluz
ID: 37833533
Assuming you only have one series associated with the chart, in the clickevent of the button to update (or the onleave event of the textbox), get the series associated with the chart, then you can set the value of theitem from there, e.g
Dim TheSeries = Chart1.Series.FirstOrDefault
'then set the value of the point
TheSeries.Points.Item(0).SetValueXY(12, "Jan")

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PS. You may need to call Invalidate on the chart to redraw after changing the points
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Author Comment

by:Terrygordon
ID: 37837725
Hi Nepaluz

I have tried a version of your suggestion, which seems to be working (once I'd remembered to call invalidate). Only problem is that the original line is staying on the chart and a new line is drawn representing the changes. I'd assumed that chart1.invalidate (), at the start of the update sub would remove the original line, but it hasn't. Any thoughts?

Regards

Terry
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LVL 17

Accepted Solution

by:
nepaluz earned 500 total points
ID: 37837886
try this
Dim TheSeries = Chart1.Series.FirstOrDefault
Chart1.Series.Clear()
TheSeries.Points.Item(0).SetValueXY(12, "Jan")
Chart1.Series.Add(TheSeries)
Chart1.Invalidate()

Open in new window

0
 

Author Comment

by:Terrygordon
ID: 37838140
Spot on! Although I had to put the Add statement before the SetValueXY statement.

Many thanks - full points on this one, but keep your eyes open, I'm about to enter more uncharted territory in the project (excuse the pun).

Regards

Terry
0

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