Adding child rows to a table using XSL

I am currently transforming XML into an HTML table using XSL.

The XML file is a collection of 'Roads' - which I am rendering out to a table.

XML: http://sandbox5.project4.net/child/roads_locs.xml
XSL: http://sandbox5.project4.net/child/roads.xsl
HTML Output: http://sandbox5.project4.net/child/default.asp

You may note in the XSL that some roads may have one or more child 'locations'.

Question: How can I modify my XSL to show 'location' information below each road row?
sonic1234Asked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Gertone (Geert Bormans)Information ArchitectCommented:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output omit-xml-declaration="yes" method="html"/> 
<xsl:template match="roads">
   
            <table class="table-j" summary="Road Closures">
               <thead>
                  <tr>
                     <th scope="col">Road Name</th>
                     <th scope="col">Council</th>
                     <th scope="col">Status</th>
                     <th scope="col">Last Updated</th>
                     <th scope="col">Last Observed</th>
                  </tr>
               </thead>
                  <tfoot>
                  <tr>
                     <td colspan="5"><em>As road conditions are constantly changing, the information shown above may not represent the actual road condition. Please drive with caution at all times.</em></td>
                  </tr>
               </tfoot>
               <tbody>
                  <xsl:apply-templates select="road"/>
               </tbody>
            </table>

    </xsl:template>
   
   <xsl:template match="road">
      <tr>
         <td>
            <b><xsl:value-of select="name"/></b>
         </td>
         <td>
            <xsl:value-of select="org"/>
         </td>
         <td>
            <xsl:value-of select="status"/>
         </td>
         <td>
            <xsl:value-of select="observed"/>
         </td>
         <td>
            <xsl:value-of select="updated"/>
         </td>
      </tr>
      <xsl:apply-templates select="locations/location"></xsl:apply-templates>
   </xsl:template>
   
   <xsl:template match="location">
      <tr>
         <td>
            <i><xsl:value-of select="name"/></i>
         </td>
         <td>
            <xsl:value-of select="org"/>
         </td>
         <td>
            <xsl:value-of select="status"/>
         </td>
         <td>
            <xsl:value-of select="observed"/>
         </td>
         <td>
            <xsl:value-of select="updated"/>
         </td>
      </tr>
   </xsl:template>
</xsl:stylesheet>

Open in new window

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
Gertone (Geert Bormans)Information ArchitectCommented:
Note that I slightly restructured your original stylesheet to use apply-templates in favour of for-each.
It greatly improves  the readibility and maintainability of your stylesheet
You pass the child nodes to a different template

Then you simply do the same with the location nodes

I made the road names bold so you see the difference
sonic1234Author Commented:
Thank you Gertone, that is very clear and helpful.
Gertone (Geert Bormans)Information ArchitectCommented:
welcome
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
XML

From novice to tech pro — start learning today.