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korn script help - AIX

Posted on 2012-04-12
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Last Modified: 2012-04-12
I have a list of LUN ID's
002D8
007A6
01245
0079E
0008E
00796
0008D
0077B
002E0
00773
00969
0076B

How do I convert into an output like this
# command " 002D8 | 007A6 | 01245 | 0079E | 0008E | 00796 | 0008D | 0077B | 002E0 | 00773 | 00969 | 0076B"
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Question by:mnis2008
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6 Comments
 
LVL 68

Expert Comment

by:woolmilkporc
ID: 37838632
awk '{if(NR==1) printf "#command \"%s | ", $0; else printf "%s | ", $0} END {print "\b\b\""} lunlist
0
 
LVL 14

Expert Comment

by:sjm_ee
ID: 37838642
cat <<! | tr "\n" "|" | sed -e "s/|/ | /g"
002D8
007A6
01245
0079E
0008E
00796
0008D
0077B
002E0
00773
00969
0076B
!
0
 
LVL 68

Accepted Solution

by:
woolmilkporc earned 2000 total points
ID: 37838660
Sorry,

I forgot the closing single quote!

awk '{if(NR==1) printf "#command \" %s | ", $0; else printf "%s | ", $0} END {print "\b\b\""}' lunlist
0
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Author Comment

by:mnis2008
ID: 37839267
Hello WMP

Thanks for your help but I wanted to output with no spaces
# command " 002D8|007A6|01245|0079E|0008E|00796|0008D|0077B|002E0|00773| 00969|0076B"

I copied and pasted from a notepad and some how we got this spaces ...
0
 
LVL 68

Expert Comment

by:woolmilkporc
ID: 37839321
No problem.

awk '{if(NR==1) printf "# command \"%s|", $0; else printf "%s|", $0} END {print "\b\""}' lunlist

I removed the space between the first quotation mark and the first LUN ID as well. Hope that's OK.
0
 

Author Comment

by:mnis2008
ID: 37839396
thanks, works now
0

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